重试Do-While循环

Question

这是一个非常简单的程序。计算机和用户在0-3之间选择一个数字。如果用户没有猜到与计算机相同的数字，我希望程序循环回来。

    String input; // input is a string variable
    int cpucrazy;
    int convertstring; 

//第一步//

    input = JOptionPane.showInputDialog("Guess a number between 0-3");
    convertstring = Integer.parseInt(input);

//随机部分//

    Random ran = new Random ();
    cpucrazy = ran.nextInt(3);

//计算！

if (cpucrazy < convertstring) {
     JOptionPane.showInputDialog(null, "Your guess is too high. Guess again?"); }


else if (cpucrazy > convertstring) {
     JOptionPane.showInputDialog(null, "Your guess is too low. Guess again?"); }


else JOptionPane.showMessageDialog(null, "Correct!!"); 

Answer 1

if (cpucrazy < convertstring) {
 JOptionPane.showInputDialog(null, "Your guess is too high. Guess again?"); }


else if (cpucrazy > convertstring) {
     JOptionPane.showInputDialog(null, "Your guess is too low. Guess again?"); }


else JOptionPane.showMessageDialog(null, "Correct!!"); 

您需要在上面的代码周围放置一个while循环(或某种类型的循环构造)，并在when：cpucrazy == convertstring或while cpucrazy != convertstring退出构造时退出该构造

该循环可能类似于以下伪代码：

b = random();

do
{
     input a;
     if( a != b )
     {
         if(a < b )
         {
              print "Too low";
         }
         else
         {
              print "Too high";
         }
     }
} while( a != b );

print "You got it correct"