函数运行函数

Question

我需要使用javascript的帮助。有没有可能这样做：

variable: {
   info1: 'info1', info2: 'info2', show: false,
   someNameFunction: functionWhichIWantRun(row)
}

之后，当我使用variable.someNameFunction()时；

它调用了我声明为functionWhichIWantRun的函数

Answer 1

someNameFunction: function (column) {
  return function(row) {
           console.log('Row: '+ row +' column:'+column);
           functionWhichIWantRun(row); // you can call other functions here
         }
}

一个简化的例子：

let row = 1;
let variable = {
           someNameFunction: function (column) {
              return function(row) {
                        console.log('Row: '+ row +' column: '+column);
                        functionWhichIWantRun(row);
                     }
           }};

let yourRowFunction = variable.someNameFunction(2);
yourRowFunction(1)// will  print "Row: 1 column: 2"

Answer 2

如果我没理解错你的问题，那么我会这样做：

​

const functionWhichIWantRun = e => console.log(e);

const variable = {
  info1: 'info1',
  info2: 'info2',
  show: false,
  someNameFunction: e => functionWhichIWantRun(e)
};

variable.someNameFunction('row 01');

​

Answer 3

我不知道你想要什么，但你可以试试我的解决方案

variable: {
   info1: 'info1', info2: 'info2', show: false,
   someNameFunction: (anotherArgs) => {
     // do something with anotherArgs
    return functionWhichIWantRun(row);
   }
}