如何在MySQL查询中分别列出每个JSON数组元素？

Question

我写了下面的MySQL Json数组查询。Mysql版本为8.0.18-commercial

select 
networkInfo->>"$.*" as network,
servers->>"$[*]" as server
from table1
where id = 56;

输出有两列JSON类型的network和server

network              server
---                  ---
[                    [
    "Linux123",          "Server123",
    "RHEL",              "Server1231",
    "abc.com"            "Server1232"
]                    ]

我想修改SELECT查询，以便每个server都有一个单独的输出行

network                      server
---                          ----  
[                             Server123
    "Linux123",
    "RHEL",
    "abc.com"
]

[                             Server1231
    "Linux123",
    "RHEL",
    "abc.com"
]

[                             Server1232
    "Linux123",
    "RHEL",
    "abc.com"
]

Answer 1

您可以使用JSON_TABLE从servers中提取不同的server值，然后将其CROSS JOIN为给定id的networks值

SELECT t1.networkInfo->>"$.*" AS network, j.server
FROM table1 t1
CROSS JOIN JSON_TABLE(t1.servers, 
                      "$[*]" COLUMNS (
                        server VARCHAR(20) PATH '$'
                        )
                      ) j
WHERE t1.id = 56

输出(我不得不根据对表结构的期望来修改demo )：

network                             server
["abc.com", "Linux123", "RHEL"]     Server123
["abc.com", "Linux123", "RHEL"]     Server1231
["abc.com", "Linux123", "RHEL"]     Server1232