如何删除bash中的多个匹配

Question

我有多个文件，结构如下：

(Genome1_Sample4A_protein_Genome1_Sample4A_132_2:0.0060449,(Genome1_Sample5A_protein_Genome1_Sample5A_30_12:1e-06,(Genome1_Sample1B_protein_Genome1_Sample1B_99_2:1e-06,Genome1_Sample6A_protein_Genome1_Sample6A_295_2:0.00366292)n2:0.00370314)n1:0.0060449)n0; 

我想把"_protein“和":”之间的部分删除。因此，输出结果如下：

(Genome1_Sample4A:0.0060449,(Genome1_Sample5A:1e-06,(Genome1_Sample1B:1e-06,Genome1_Sample6A:0.00366292)n2:0.00370314)n1:0.0060449)n0; 

我尝试使用sed和awk：

sed -i 's/_protein.*:/:/g' tree1.txt

sed -i 's/_protein.*_[[:digit:]]*:/:/g' tree1.txt

awk '{gsub(/\_protein*:/,":");}1' tree1.txt

但是这些代码中的任何一个都给了我想要的输出。

Answer 1

.*是greedy，所以改用下面的代码：

sed 's/_protein[^:]*:/:/g' tree1.txt

输出：

(Genome1_Sample4A:0.0060449,(Genome1_Sample5A:1e-06,(Genome1_Sample1B:1e-06,Genome1_Sample6A:0.00366292)n2:0.00370314)n1:0.0060449)n0;