在windows上使用bash递归地重命名文件目录

Question

├── package-1
│   └── src
│       ├── controllers
│       ├── models
│       |── traits
│       └── views
├── package-2
│   └── src
│       ├── controllers
│       ├── models
│       |── traits
│       └── views
├── package-3
│   └── src
│       ├── controllers
│       ├── models
│       |── traits
│       └── views

我想以递归方式将文件夹controllers重命名为Controllers、models和Models

从各种文章，例如https://askubuntu.com/questions/56326/how-do-i-rename-a-directory-via-the-command-line和帖子中，我可以看到我需要使用rm，所以我运行了以下命令

for i in */src/controllers/; 
  do  mv $i /Controllers/; 
done

下面是我面临的错误

mv: cannot move 'laravel-files/src/controllers/' to '/Controllers/controllers': Directory not empty
mv: cannot move 'laravel-guardian-admissions/src/controllers/' to '/Controllers/controllers': Directory not empty
mv: cannot move 'laravel-guardians/src/controllers/' to '/Controllers/controllers': Directory not empty
mv: cannot move 'laravel-lms/src/controllers/' to '/Controllers/controllers': Directory not empty
mv: cannot move 'laravel-permissions-and-roles/src/controllers/' to '/Controllers/controllers': Directory not empty
mv: cannot move 'laravel-procurements/src/controllers/' to '/Controllers/controllers': Directory not empty
mv: cannot move 'laravel-school-accounts/src/controllers/' to '/Controllers/controllers': Directory not empty
mv: cannot move 'laravel-school-curriculum/src/controllers/' to '/Controllers/controllers': Directory not empty
mv: cannot move 'laravel-school-exams/src/controllers/' to '/Controllers/controllers': Directory not empty
mv: cannot move 'laravel-school-infrastructures/src/controllers/' to '/Controllers/controllers': Directory not empty
mv: cannot move 'laravel-school-streams/src/controllers/' to '/Controllers/controllers': Directory not empty

请帮助我指出我在实现中出错的地方。

Answer 1

由于mv $i /Controllers/中的前导/，您可以将每个$i移到完全相同的目录中，即文件系统最顶端的一个名为Controllers的目录。

可以使用cd进入每个目录并使用相对路径(cd "$i/.."; mv "$i" Controllers; cd -)，也可以使用bash的参数扩展来修改路径：

for i in */src/controllers/; do
  mv "$i" "${i/\/c/\/C}"
done

${i/\/c/\/C}将第一个/c替换为/C。

Answer 2

如果您安装了GNU parallel，您可以尝试：

find . -regextype posix-extended -regex '.*/(controlers|models|traits|views)' | 
    parallel echo mv {} {= 's[(.*/)(.+)][${1} . ucfirst($2)]e' =}

如果结果是预期的，则删除echo。