请求库和except

Question

所有人。我花了几周的时间学习Python。我有一个关于请求库的问题。我写了一个简短的代码，要求输入网站地址。如果该页存在，则将其写入文件good.txt，如果该页不存在，则将其写入wrong.txt文件。这段代码有什么问题？

import requests


website = input('First website to check:  ')

website1 = 'http://'+website

a = requests.get(website1)



try:
    a.status_code  == 200
    with open("good.txt", "a", encoding = "UTF-8") as file:
         file.write(website1)

except requests.RequestException:
    with open("wrong.txt", "a", encoding = "UTF-8") as file:
         file.write(website1)

谢谢你的建议。

Answer 1

使用try/except块，您必须在try块中发出请求。

import requests


website = input('First website to check:  ')

website1 = 'http://'+website
try:
    a = requests.get(website1)
    a.status_code  == 200
    with open("good.txt", "a", encoding = "UTF-8") as file:
         file.write(website1)

except requests.RequestException:
    with open("wrong.txt", "a", encoding = "UTF-8") as file:
         file.write(website1)

Answer 2

您需要创建一个if语句

try:
    a = requests.get(website1)
    if a.status_code  == 200:
        with open("good.txt", "a", encoding = "UTF-8") as file:
            file.write(website1)
    else:
        with open("wrong.txt", "a", encoding = "UTF-8") as file:
            file.write(website1)

except requests.RequestException:
    with open("wrong.txt", "a", encoding = "UTF-8") as file:
        file.write(website1)

编辑:还修复了try catch代码