我的剪刀石头布AI脚本不工作

Question

所以基本上我一直在用python做一个AI岩布剪刀脚本，它可以工作，但只选择了纸，我需要它来选择不同的东西。问题在第29行和第46行之间。可能有一个简单的解决方案，但我似乎找不到它。请帮我编写noobie代码。

import random
import numpy as np
import matplotlib.pyplot as plt

x = 1

paper = 0
rock = 0
scissors = 0

plist = []

result = ""
def percentage(item, result):
    total = rock + paper + scissors
    result = item / total * 10
while x == 1:

    print(" ")
    ui = input("Rock, Paper, Scissors: ")
    if ui == "Rock":
        rock += 1
    elif ui == "Paper":
        paper += 1
    elif ui == "Scissors":
        scissors += 1



    plist.append(ui)

    plist = ["Rock", "Scissors", "Rock", "Rock", "Paper"]

    if plist[0] == "Rock":
        aio = "Paper"
        plist.pop(0)
    elif plist[0] == "Paper":
        aio = "Scissors"
        plist.pop(0)
    elif plist[0] == "Scissors":
        aio = "Rock"
        plist.pop(0)

    print(" ")
    print("AI chose " + aio)
    print(" ")
    if aio == "Rock" and ui == "Paper":
        print("You won")
    elif aio == "Paper" and ui == "Scissors":
        print("You won")
    elif aio == "Scissors" and ui == "Rock":
        print("You won")
    elif aio == "Paper" and ui == "Rock":
        print("You lost")
    elif aio == "Scissors" and ui == "Paper":
        print("You lost")
    elif aio == "Rock" and ui == "Scissors":
        print("You lost")
    elif aio == "Paper" and ui == "Paper":
        print("You tied")
    elif aio == "Scissors" and ui == "Scissors":
        print("You tied")
    elif aio == "Rock" and ui == "Rock":
        print("You tied")

Answer 1

不清楚你的AI到底应该做什么，但现在它总是选择Paper，因为在每个循环中你总是这样做：

    plist = ["Rock", "Scissors", "Rock", "Rock", "Paper"]

    if plist[0] == "Rock":
        aio = "Paper"

对于这段代码，plist[0]只能是Rock --不管您以前给它分配了什么，每次进行比较之前都要将它重新分配给这个静态列表(从它pop和append到它都没有关系，因为在下次查看它之前会覆盖整个内容)。由于不清楚plist的用途，我建议直接摆脱它，并使用random.choice来挑选AI的投掷：

import random

while True:
    ui = input("\nRock, Paper, Scissors: ")
    aio = random.choice(["Rock, Paper, Scissors"])

    print(f"\nAI chose {aio}\n")
    if aio == "Rock" and ui == "Paper":
        print("You won")
    elif aio == "Paper" and ui == "Scissors":
        print("You won")
    elif aio == "Scissors" and ui == "Rock":
        print("You won")
    elif aio == "Paper" and ui == "Rock":
        print("You lost")
    elif aio == "Scissors" and ui == "Paper":
        print("You lost")
    elif aio == "Rock" and ui == "Scissors":
        print("You lost")
    elif aio == "Paper" and ui == "Paper":
        print("You tied")
    elif aio == "Scissors" and ui == "Scissors":
        print("You tied")
    elif aio == "Rock" and ui == "Rock":
        print("You tied")
    else:
        print(f"You picked {ui}, which was not one of the choices.")

Answer 2

在每个循环中都定义了plist，因此plist[0]始终为'Rock'。

如果从循环中删除plist = ["Rock", "Scissors", "Rock", "Rock", "Paper"]，它应该可以正常工作。