首页
学习
活动
专区
圈层
工具
发布
社区首页 >问答首页 >如何通过复制值来pivot_wider和填充缺少的值

如何通过复制值来pivot_wider和填充缺少的值
EN

Stack Overflow用户
提问于 2020-09-03 07:43:49
回答 1查看 122关注 0票数 0

我试图获得一个从长到宽的数据帧,但是由于它的结构,每当我使用pivot_wider()时,我都会得到两列包含数据向量的数据。

以下是原始数据:

代码语言:javascript
复制
structure(list(type = c("radio", "radio", "radio", "television", 
"television", "television", "television", "television", "television", 
"television", "television", "television", "television", "television", 
"television", "television", "television", "television", "television"
), Resource = c("samsung", "samsung", "samsung", "samsung", "samsung", 
"samsung", "samsung", "samsung", "samsung", "samsung", "samsung", 
"sony", "sony", "sony", "sony", "sony", "sony", "sony", "sony"
), Property = c("lot_number", "lot_number", "manufacturer", "lot_number", 
"lot_number", "lot_number", "lot_number", "lot_number", "manufacturer", 
"other_PN", "part_number", "lot_number", "lot_number", "lot_number", 
"lot_number", "lot_number", "manufacturer", "other_PN", "part_number"
), value = c("12345", "54321", "John", "9876", "12345", "54321", 
"56789", "67890", "Walt", "5g6h3f", "6789", "9876", "12345", 
"54321", "56789", "67890", "John", "2a3b4c", "3461")), class = c("spec_tbl_df", 
"tbl_df", "tbl", "data.frame"), row.names = c(NA, -19L), spec = structure(list(
    cols = list(type = structure(list(), class = c("collector_character", 
    "collector")), Resource = structure(list(), class = c("collector_character", 
    "collector")), Property = structure(list(), class = c("collector_character", 
    "collector")), value = structure(list(), class = c("collector_character", 
    "collector"))), default = structure(list(), class = c("collector_guess", 
    "collector")), skip = 1), class = "col_spec"))

我使用的命令:

代码语言:javascript
复制
df_wide <- df %>% pivot_wider(names_from = Property, values_from = value)

但是多个值被保存为"lot_number“列中的一个向量:

代码语言:javascript
复制
structure(list(type = c("radio", "television", "television"), 
    Resource = c("samsung", "samsung", "sony"), lot_number = list(
        c("12345", "54321"), c("9876", "12345", "54321", "56789", 
        "67890"), c("9876", "12345", "54321", "56789", "67890"
        )), manufacturer = list("John", "Walt", "John"), other_PN = list(
        NULL, "5g6h3f", "2a3b4c"), part_number = list(NULL, "6789", 
        "3461")), row.names = c(NA, -3L), class = c("tbl_df", 
"tbl", "data.frame"))

这是我想在最后得到的数据帧。请注意,在所需的输出中,"radio“有一些缺失值。此外,列"manufacturer“、"other_PN”和"part_number“中的值必须在多个行中重复。

代码语言:javascript
复制
structure(list(type = c("radio", "radio", "television", "television", 
"television", "television", "television", "television", "television", 
"television", "television", "television"), Resource = c("samsung", 
"samsung", "samsung", "samsung", "samsung", "samsung", "samsung", 
"sony", "sony", "sony", "sony", "sony"), manufacturer = c("John", 
"John", "Walt", "Walt", "Walt", "Walt", "Walt", "John", "John", 
"John", "John", "John"), other_PN = c(NA, NA, "5g6h3f", "5g6h3f", 
"5g6h3f", "5g6h3f", "5g6h3f", "2a3b4c", "2a3b4c", "2a3b4c", "2a3b4c", 
"2a3b4c"), part_number = c(NA, NA, 6789, 6789, 6789, 6789, 6789, 
3461, 3461, 3461, 3461, 3461), lot_number = c(12345, 54321, 9876, 
12345, 54321, 56789, 67890, 9876, 12345, 54321, 56789, 67890)), class = c("spec_tbl_df", 
"tbl_df", "tbl", "data.frame"), row.names = c(NA, -12L), spec = structure(list(
    cols = list(type = structure(list(), class = c("collector_character", 
    "collector")), Resource = structure(list(), class = c("collector_character", 
    "collector")), manufacturer = structure(list(), class = c("collector_character", 
    "collector")), other_PN = structure(list(), class = c("collector_character", 
    "collector")), part_number = structure(list(), class = c("collector_double", 
    "collector")), lot_number = structure(list(), class = c("collector_double", 
    "collector"))), default = structure(list(), class = c("collector_guess", 
    "collector")), skip = 1), class = "col_spec"))

感谢您的帮助!!

EN

回答 1

Stack Overflow用户

回答已采纳

发布于 2020-09-03 07:54:49

我建议使用dput()数据作为df来使用这种方法。您可以使用group_by()创建一个id变量来标识行,然后可以使用pivot_wider()进行整形。由于需要填充一些值,您可以使用tidyr中的fill(),这是一个tidyverse包:

代码语言:javascript
复制
library(tidyverse)
#Data
df %>% group_by(type,Resource,Property) %>% mutate(id=1:n()) %>%
  pivot_wider(names_from = Property,values_from=value) %>%
  fill(everything()) %>% select(-id)

输出:

代码语言:javascript
复制
# A tibble: 12 x 6
# Groups:   type, Resource [3]
   type       Resource lot_number manufacturer other_PN part_number
   <chr>      <chr>    <chr>      <chr>        <chr>    <chr>      
 1 radio      samsung  12345      John         NA       NA         
 2 radio      samsung  54321      John         NA       NA         
 3 television samsung  9876       Walt         5g6h3f   6789       
 4 television samsung  12345      Walt         5g6h3f   6789       
 5 television samsung  54321      Walt         5g6h3f   6789       
 6 television samsung  56789      Walt         5g6h3f   6789       
 7 television samsung  67890      Walt         5g6h3f   6789       
 8 television sony     9876       John         2a3b4c   3461       
 9 television sony     12345      John         2a3b4c   3461       
10 television sony     54321      John         2a3b4c   3461       
11 television sony     56789      John         2a3b4c   3461       
12 television sony     67890      John         2a3b4c   3461   
票数 0
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/63714874

复制
相关文章

相似问题

领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档