我已经绞尽脑汁想了一段时间了,如果有任何帮助,我将不胜感激。
我正在使用React和Redux Toolkit,我正在努力让React从我的UI中删除一个'todo‘,尽管Redux的响应与预期一致。在Redux开发人员工具中,removeTodo按预期工作,从待办事项数组状态中删除待办事项,但React不会跟随,因此我的UI也不会随之改变。我的addTodo操作在React和Redux中都能正常工作。
当我单击调用removeTodo调度的按钮时,我当前的代码提供了以下错误。
TypeError: Cannot read property 'length' of undefined
App
C:/Users/joeee/Documents/redux-middleware/src/app/App.js:13
10 |
11 | return (
12 | <div style={divStyles}>
> 13 | <TodosForm />
| ^ 14 | {todos.length > 0 && <TodoList />}
15 | </div>
16 | )
View compiled
▶ 19 stack frames were collapsed.需要注意的是,只有当todos数组状态的长度大于0时,我才会在TodoList组件中呈现,因为我不希望在没有todo时呈现该组件。我是React和Redux的新手,可能有一个非常简单的解决方案,但从我能破解的是,当调用removeTodo时,todos数组状态将被完全移除,而不是返回id不等于传入的id的那些。这就是为什么我假设我得到的错误告诉我它不能读取未定义的.length,因为我的待办事项状态现在是空的。
我删除了todos.length必须大于0才能呈现TodoList的要求,但随后我得到了错误,它无法读取TodoList中未定义(我的待办事项状态)的.map,这对我来说,这强化了我的整个待办事项状态似乎正在被删除。
这是我的todosSlice:
import { createSlice } from '@reduxjs/toolkit';
export const todosSlice = createSlice({
name: 'todos',
initialState: {
todos: [],
},
reducers: {
addTodo: (state, action) => {
const { id, task } = action.payload;
state.todos.push({ id, task })
},
removeTodo: (state, action) => {
// console.log(state.todos);
const { id } = action.payload;
// console.log(id);
return state.todos.filter(item => item.id !== id);
}
},
});
export const selectTodos = state => state.todos.todos;
export const { addTodo, removeTodo } = todosSlice.actions;
export default todosSlice.reducer; App.js:
import React from 'react';
import { useSelector } from 'react-redux';
import TodosForm from '../components/TodosForm';
import TodoList from '../components/TodoList';
import { selectTodos } from '../features/todosSlice';
export const App = () => {
const todos = useSelector(selectTodos);
// console.log(todos.length);
return (
<div style={divStyles}>
<TodosForm />
{todos.length > 0 && <TodoList />}
</div>
)
}
export default App;TodoList.js
import React from 'react';
import { useSelector } from 'react-redux';
import { selectTodos } from '../features/todosSlice';
import Todos from './Todos';
const TodoList = () => {
const todos = useSelector(selectTodos);
// console.log(todos);
return (
<div style={divStyles}>
<h3 style={headerStyles}>Your Todos: </h3>
{todos.map(todo => <Todos key={todo.id} task={todo.task} id={todo.id} />)}
</div>
)
}
export default TodoListTodos.js
import React from 'react';
import { useDispatch } from 'react-redux';
import { FontAwesomeIcon } from '@fortawesome/react-fontawesome'
import { faTrashAlt } from '@fortawesome/free-solid-svg-icons'
import { faEdit } from '@fortawesome/free-solid-svg-icons'
import { removeTodo } from '../features/todosSlice';
const Todos = ({ task, id }) => {
const dispatch = useDispatch();
const handleDeleteClick = () => {
dispatch(removeTodo({id: id}));
}
return (
<div style={divStyles}>
<li style={listStyles}>{task}</li>
<div>
<button className="faEditIcon" style={btnStyles}><FontAwesomeIcon icon={faEdit}/></button>
<button className="faDeleteIcon" style={btnStyles} onClick={handleDeleteClick}><FontAwesomeIcon icon={faTrashAlt}/></button>
</div>
</div>
)
}
export default Todos;还有我的store.js
import { configureStore } from '@reduxjs/toolkit';
import todosSliceReducer from '../features/todosSlice';
export default configureStore({
reducer: {
todos: todosSliceReducer,
},
});发布于 2021-07-07 18:57:43
你能像下面这样更新removeTodo并查看吗?
removeTodo: (state, action) => {
// console.log(state.todos);
const { id } = action.payload;
// console.log(id);
state.todos = state.todos.filter(item => item.id !== id)
}https://stackoverflow.com/questions/68284530
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