Scala Play JSON:将hashmap转换为json对象，而不是数组

Question

对于给定的HashMap结构：

scala.collection.immutable.Map[scala.Option[java.util.UUID], scala.collection.immutable.List[crm.v1.auto.generated.customapis.CustomapisPublic]]

Json.toJson会产生这样的结果：

[
    [
        "bb2b5475-8f27-4dd4-9221-05904177a666",
        [
            {
                "id": "5e700dab-e352-47d5-8ad8-0d9e16db8fbc",
                "time": 1616500566442,
                "isGroup": true,
                "name": "rapidx",
                "parentId": "bb2b5475-8f27-4dd4-9221-05904177a666",
                "projectId": "d531e915-afb0-42e9-9c90-831f0413794e",
                "teamId": "a03339d4-4ccc-48ea-8bd9-b506ad83c492"
            },
            {
                "id": "5287f6bd-2f55-4232-9064-a989ae5926f3",
                "time": 1616503457651,
                "isGroup": true,
                "name": "User",
                "parentId": "bb2b5475-8f27-4dd4-9221-05904177a666",
                "projectId": "d531e915-afb0-42e9-9c90-831f0413794e",
                "teamId": "a03339d4-4ccc-48ea-8bd9-b506ad83c492"
            }
        ]
    ],
    [
        "5287f6bd-2f55-4232-9064-a989ae5926f3",
        [
            {
                "id": "db0f59ea-fbf0-4024-ad54-04ea387223b0",
                "time": 1616569959967,
                "description": "Post Daily data",
                "isGroup": true,
                "name": "Post Daily data",
                "parentId": "5287f6bd-2f55-4232-9064-a989ae5926f3",
                "projectId": "d531e915-afb0-42e9-9c90-831f0413794e",
                "teamId": "a03339d4-4ccc-48ea-8bd9-b506ad83c492"
            },
            {
                "id": "325c3d1f-d2bb-46b2-a708-db26484607c2",
                "time": 1616570029306,
                "code": "Future{\n    Results.Ok(“Patch user data working successfully”)\n}",
                "description": "patch user data",
                "isGroup": false,
                "name": "patch user data",
                "parentId": "5287f6bd-2f55-4232-9064-a989ae5926f3",
                "projectId": "d531e915-afb0-42e9-9c90-831f0413794e",
                "supportedMethods": [
                    "get",
                    "post",
                    "patch",
                    "delete"
                ],
                "teamId": "a03339d4-4ccc-48ea-8bd9-b506ad83c492"
            },
            {
                "id": "61c392b5-b482-4b2b-be2c-e94f40dfef2c",
                "time": 1616570221882,
                "code": "Future{Results.Ok(“Add config working successfully”)}",
                "description": "addConfig",
                "isGroup": false,
                "name": "addConfig",
                "parentId": "5287f6bd-2f55-4232-9064-a989ae5926f3",
                "projectId": "d531e915-afb0-42e9-9c90-831f0413794e",
                "teamId": "a03339d4-4ccc-48ea-8bd9-b506ad83c492"
            }
        ]
    ]]

而我想要像他那样的东西：

{
 "uuid-1": [{...object-1...}, ...],
 "uuid-2": [{...object 1...}, ...],
 "uuid-n": [{...object 1...}, ...],
 null: [{...object 1}, .... ]
}

我们将非常感谢您的任何建议。

Answer 1

PlayJson知道如何使用Map[String, SomethingThatHasAWrites]，所以您可以先将键转换为String。

虽然不确定如何处理null，但这似乎不是一个好主意，也许可以更改为一个虚拟值？

 Json.toJson(data.map { 
    case (Some(key), value) => key.toString -> value 
    case (None, value)      => "missing"    -> value
 })

Answer 2

巧合的是，我尝试了一些类似@Thilo刚才建议的东西。

我在我的组之后添加了一个映射，并将键类型OptionUUID转换为String。

mapField.map(a  => (a._1.map(_.toString).getOrElse("root"), a._2))

我也意识到PlayJson在这里真的很聪明，当有空值时，它选择了基于列表/数组的结构。现在，当没有机会用空值代替key时，它选择了树/对象结构。

也许，我猜当有非基于字符串的类型代替HashMap键时，PlayJson选择列表结构，而如果HashMap键的类型是数字或字符串，则选择树结构。

新结构如下所示：

{
    "root": [
        {....},
        {....},
        {....}
    ],
    "db0f59ea-fbf0-4024-ad54-04ea387223b0": [
        {...}
    ],