我确实构建了一个不和谐的机器人,我想添加一个命令来运行和读取python中的另一个脚本输出,我该如何做呢?这是我关于不一致的新机器人
import discord
from discord.ext import commands, tasks
import discord
from discord.ext import commands, tasks
from itertools import cycle
flashing = commands.Bot(command_prefix='.')
@flashing.command()
async def ping(ctx):
await ctx.send(f'Pong! {round(flashing.latency * 1000)} ms' )
print('bot is ready.')
@flashing.event
async def on_ready():
change_status.start()
flashing.run('token')另一个脚本名称为base_script.py
发布于 2020-09-01 20:34:20
假设这两个脚本位于同一文件夹中:
#scripts.py
def Some_Code():
#Put all of scripts.py code in this function
return(Variables)
#make sure to return all variable that you want to read in your other file假设您已经这样设置了scripts.py,剩下的就很简单了:
import scripts
print(scripts.Some_Code())https://stackoverflow.com/questions/63687442
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