Tac-Toe Player vs AI -- AI问题

Question

这是一个C语言的玩家vs AI tic-tac-toe游戏。如果AI滚动到一个被占用的位置，我如何让它再次滚动，直到它到达一个空置的位置？

char boardchar[3][3] = { {'1', '2', '3'}, {'4', '5', '6'}, {'7', '8', '9'} }; 


void Turn()
{
    /*Player's Turn*/

    AIrandomizer();
    AI = AI_roll();


        if (AI == 1 && boardchar[0][0] == '1')
        {
            boardchar[0][0] = symbAI;
        }

        else if (AI == 2 && boardchar[0][1] == '2')
        {
            boardchar[0][1] = symbAI;                   
        }


        else if (AI == 3 && boardchar[0][2] == '3')
        {
            boardchar[0][2] = symbAI;               
        }


        else if (AI == 4 && boardchar[1][0] == '4')
        {
            boardchar[1][0] = symbAI;       
        }

        else if (AI == 5 && boardchar[1][1] == '5')
        {
            boardchar[1][1] = symbAI;               
        }


        else if (AI == 6 && boardchar[1][2] == '6')
        {
            boardchar[1][2] = symbAI;               
        }

        else if (AI == 7 && boardchar[2][0] == '7')
        {
            boardchar[2][0] = symbAI;               
        }

        else if (AI == 8 && boardchar[2][1] == '8')
        {
            boardchar[2][1] = symbAI;               
        }

        else if (AI == 9 && boardchar[2][2] == '9')
        {
            boardchar[2][2] = symbAI;           
        }

}

我已经尝试了switch(case)和多个I和else I，但我仍然想不出解决这个问题的方法。

Answer 1

您可以使用while或do-while语句。

还要制作一个3x3的二维数组来跟踪这些点:0=未填充，1=人类，2= AI (更好的方法是使用枚举)。

在伪代码中：

全局变量：

int spots[3][3]; // 3x3 array

代码：

Setup(); // Setup of board, sets 0's to spots.

while (!endOfGame())
{
    Player(); // Handle player, assuming it plays first, sets a 1 in one spot

    if (!endOfGame())
    {
         AI();
    }
}


void AI() 
{
    do
    {
       square = AIChoice();
    } while (spots[square] == 0);

    // Now we know spots[square] == 0, thus unfilled
    spots[square] = 2; // AI
}