cipher python未返回权限

Question

没有得到正确的结果，需要解密代码的帮助

# need help with code
cipher = ''
decipher = ''
choice = ''
while choice != 0:
    choice = input('Press 1 to encrypt your text \nPress 2 to decrypt your 
    cipher text \n:')
    if choice == '1':
        cipher = input('Enter text to encrypt').lower()
        for letter in cipher:
            if(letter != ''):
                cipher += the_bacon[letter]
        print(cipher)
    break

>>> Press 1 to encrypt your text 
>>> Press 2 to decrypt your cipher text 
:1
>>> Enter text to encrypt
hello world
hello worldaabbb
hello worldaabbbaabaa
hello worldaabbbaabaaababb
hello worldaabbbaabaaababbababb
hello worldaabbbaabaaababbababbabbba

需要创建替代培根密码和它不能正常工作，也需要帮助与解密代码

Answer 1

假设您的the_bacon是一个具有1对1字母交换的适当字典，那么您的问题在于您是附加在输入上，而不是创建一个新的输出对象，然后将其打印出来。

您还可以使用while not choice:来表示循环，直到它们响应为止。除非你打算先把它转换成int类型，否则!= 0永远不会发生。

cipher = ''
decipher = ''
choice = ''
while not choice:
    choice = input('Press 1 to encrypt your text \nPress 2 to decrypt your 
    cipher text \n:')
    if choice == '1':
        in_cipher = input('Enter text to encrypt').lower()
        out_cipher = ''
        for letter in in_cipher:
            if(letter != ' '):
                out_cipher += the_bacon[letter]
                print(out_cipher) # print output letter by letter as it builds
        print(out_cipher) # print the output
    else:
        # you need to decipher here and handle choices not 1 or 2