当我使用sinatra运行我的应用程序时,当我点击/users/new路由上的提交按钮时,我得到了错误消息PG::SyntaxError at /bookmarks ERROR: syntax error at or near "{" LINE 1: SELECT * FROM users WHERE id = {:id=>"5"} ^ It happens,这应该会把我带到索引路由/。
回溯提供了以下信息
/Users/BartJudge/Desktop/Makers_2018/bookmark-manager-2019/lib/database_connection.rb in async_exec @connection.exec(sql)
/Users/BartJudge/Desktop/Makers_2018/bookmark-manager-2019/lib/database_connection.rb in query @connection.exec(sql)
/Users/BartJudge/Desktop/Makers_2018/bookmark-manager-2019/lib/user.rb in find result = DatabaseConnection.query("SELECT * FROM users WHERE id = #{id}") app.rb in block in <class:BookmarkManager> @user = User.find(id: session[:user_id])
这是database_connection文件
require 'pg'
class DatabaseConnection
def self.setup(dbname)
@connection = PG.connect(dbname: dbname)
end
def self.connection
@connection
end
def self.query(sql)
@connection.exec(sql)
end
end这是用户模型
require_relative './database_connection'
require 'bcrypt'
class User
def self.create(email:, password:)
encypted_password = BCrypt::Password.create(password
)
result = DatabaseConnection.query("INSERT INTO users (email, password) VALUES('#{email}', '#{encypted_password}') RETURNING id, email;")
User.new(id: result[0]['id'], email: result[0]['email'])
end
attr_reader :id, :email
def initialize(id:, email:)
@id = id
@email = email
end
def self.find(id)
return nil unless id
result = DatabaseConnection.query("SELECT * FROM users WHERE id = #{id}")
User.new(
id: result[0]['id'],
email: result[0]['email'])
end
end这是控制器
require 'sinatra/base'
require './lib/bookmark'
require './lib/user'
require './database_connection_setup.rb'
require 'uri'
require 'sinatra/flash'
require_relative './lib/tag'
require_relative './lib/bookmark_tag'
class BookmarkManager < Sinatra::Base
enable :sessions, :method_override
register Sinatra::Flash
get '/' do
"Bookmark Manager"
end
get '/bookmarks' do
@user = User.find(id: session[:user_id])
@bookmarks = Bookmark.all
erb :'bookmarks/index'
end
post '/bookmarks' do
flash[:notice] = "You must submit a valid URL" unless Bookmark.create(url: params[:url], title: params[:title])
redirect '/bookmarks'
end
get '/bookmarks/new' do
erb :'bookmarks/new'
end
delete '/bookmarks/:id' do
Bookmark.delete(id: params[:id])
redirect '/bookmarks'
end
patch '/bookmarks/:id' do
Bookmark.update(id: params[:id], title: params[:title], url: params[:url])
redirect('/bookmarks')
end
get '/bookmarks/:id/edit' do
@bookmark = Bookmark.find(id: params[:id])
erb :'bookmarks/edit'
end
get '/bookmarks/:id/comments/new' do
@bookmark_id = params[:id]
erb :'comments/new'
end
post '/bookmarks/:id/comments' do
Comment.create(text: params[:comment], bookmark_id: params[:id])
redirect '/bookmarks'
end
get '/bookmarks/:id/tags/new' do
@bookmark_id = params[:id]
erb :'/tags/new'
end
post '/bookmarks:id/tags' do
tag = Tag.create(content: params[:tag])
BookmarkTag.create(bookmark_id: params[:id], tag_id: tag.id)
redirect '/bookmarks'
end
get '/users/new' do
erb :'users/new'
end
post '/users' do
user = User.create(email: params[:email], password: params[:password])
session[:user_id] = user.id
redirect '/bookmarks'
end
run! if app_file == $0
end在用户模型中,self.find(id)是可能有问题的SQL查询所在的位置。
我已经尝试过了;"SELECT * FROM users WHERE id = #{id}“
和"SELECT * FROM users WHERE id = '#{id}'“
除此之外,我被难住了。查询看起来很好,但是sinatra没有。
希望有人能帮我解决这个问题。谢谢,提前说好。
发布于 2019-05-09 04:59:32
您正在使用散列参数调用find:
User.find(id: session[:user_id])但它期望的只是id
class User
...
def self.find(id)
...
end
...
end然后,您最终在SQL字符串中插入一个散列,这将导致无效的HTML。
你应该说:
@user = User.find(session[:user_id])仅传入User.find期望的id。
您还可能会遇到SQL注入问题,因为您在查询中使用的是不受保护的字符串插值,而不是占位符。
您的query方法应该使用exec_params而不是exec,并且它应该为占位符值使用一些额外的参数:
class DatabaseConnection
def self.query(sql, *values)
@connection.exec_params(sql, values)
end
end然后,调用query的东西应该在SQL中使用占位符,并分别传递这些值:
result = DatabaseConnection.query(%q(
INSERT INTO users (email, password)
VALUES($1, $2) RETURNING id, email
), email, encypted_password)
result = DatabaseConnection.query('SELECT * FROM users WHERE id = $1', id)
...https://stackoverflow.com/questions/56044871
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