PVMismatch中gen_coeffs.gen_two_diode的输出是什么意思？

Question

我不理解gen_coeffs.gen_two_diode的输出，它是：

fjac: array([[nan, nan, nan, nan, nan, nan, nan, nan, nan, nan, nan, nan, nan,nan, nan, nan, nan, nan, nan, nan, nan, nan, nan, nan, nan, nan, nan,
    ... nan, nan, nan, nan, nan, nan, nan, nan]])
         fun: array([-5.00391537e-02, -5.32664899e-02, -5.71223793e-02, -  5.97740265e-02,-6.18808152e-02, -6.36665900e-02...-1.94677609e-07,
    -2.92041963e-07, -3.89423353e-07, -4.86821782e-07, -5.35527386e-07])
        ipvt: array([1, 2, 3, 4], dtype=int32)
    message: 'The cosine of the angle between func(x) and any column of the\n  Jacobian is at most 0.000000 in absolute value'
      nfev: 1
      njev: 1
      qtf: array([nan, nan, nan, nan])
      status: 4
    success: True
    x: array([-24.51750581, -13.41004545,   0.06324555,   3.16227766])

我能在这个输出中找到我需要的值(Isat1，Isat2，Rs和Rs)吗？或者在使用gen_coeffs.gen_two_diode之后，我可以在哪里找到2二极管模型所需的参数？

Answer 1

输出是解算器的Scipy方法的典型输出。我要查找的值在x数组中-24.51750581，-13.41004545，0.06324555，3.16227766。但有一点加密：

饱和电流的计算结果用e函数的指数表示，并联电阻和串联电阻用均方根表示。

isat1 = np.exp(sol.x[0])
isat2 = np.exp(sol.x[1])
rs = sol.x[2] ** 2.0
rsh = sol.x[3] ** 2.0