首页
学习
活动
专区
圈层
工具
发布
社区首页 >问答首页 >抓取Python Web抓取JSON

抓取Python Web抓取JSON
EN

Stack Overflow用户
提问于 2020-09-10 22:30:35
回答 1查看 52关注 0票数 0

我正在努力找出如何使用Scrapy Python抓取JSON响应。我能够成功地在同一站点的不同页面上抓取JSON。如果有任何帮助,我将不胜感激。

我如何抓取"tournamentGroup“中的值(即id、name)以及年份、标题等。

部分代码:

代码语言:javascript
复制
start_url = 'https://api.wtatennis.com/tennis/tournaments/?page=0&pageSize=100&excludeLevels=ITF&from=2020-09-01&to=2020-09-30'
    
with urllib.request.urlopen(start_url) as start_url:
    json_obj = start_url.read()
    rank_list = json.loads(json_obj)

    for item in rank_list:
        
        rank_data = []
        tourney_id = item['content']['id']
        tourney_year = item['year']
    
        rank_data = [tourney_id, tourney_year]
 
        cur.execute("""insert into wta_rankings(tourney_id, tourney_year) 
                    values(%s, %s)
                    ON CONFLICT DO NOTHING"""
                    ,(rank_data))
        conn.commit()        
    cur.close()

JSON:
{
   "pageInfo":{
      "page":0,
      "numPages":0,
      "pageSize":100,
      "numEntries":10
   },
   "content":[
      {
         "tournamentGroup":{
            "id":2023,
            "name":"Prague 125K",
            "level":"125K",
            "metadata":null
         },
         "year":2020,
         "title":"Prague Open",
         "startDate":"2020-08-29",
         "endDate":"2020-09-06",
         "surface":"Clay",
         "inOutdoor":"O",
         "city":"PRAGUE",
         "country":"Czech Republic",
         "singlesDrawSize":128,
         "doublesDrawSize":32,
         "prizeMoney":3125000,
         "prizeMoneyCurrency":"USD",
         "liveScoringId":"2023"
      },

URL示例:https://api.wtatennis.com/tennis/tournaments/?page=0&pageSize=100&excludeLevels=ITF&from=2020-09-01&to=2020-09-30

EN

回答 1

Stack Overflow用户

回答已采纳

发布于 2020-09-10 22:38:27

试试这个:

代码语言:javascript
复制
import requests

url = "https://api.wtatennis.com/tennis/tournaments/?page=0&pageSize=100&excludeLevels=ITF&from=2020-09-01&to=2020-09-30"

response = requests.get(url).json()

for item in response["content"]:
    print(f"{item['tournamentGroup']['name']} - {item['year']} - {item['title']}")

这为您提供了(这只是一个示例,您可以获得任何您想要的字段):

代码语言:javascript
复制
Prague 125K - 2020 - Prague Open
US OPEN - 2020 - US Open - New York, United States, NY
WARSAW - 2020 - BNP Paribas Warsaw Open - Warsaw, Poland
ISTANBUL - 2020 - TEB BNP Paribas Tennis Championship Istanbul - Istanbul, Turkey
MADRID - 2020 - Mutua Madrid Open - Madrid, Spain
HIROSHIMA - 2020 - Hana-cupid Japan Women's Open - Hiroshima, Japan
ROME - 2020 - Internazionali BNL d'Italia - Rome, Italy
STRASBOURG - 2020 - Internationaux de Strasbourg - Strasbourg, France
ROLAND GARROS - 2020 - Roland Garros - Paris, France
TASHKENT - 2020 - Tashkent Open - Tashkent, Uzbekistan

如果您很难在JSON中“导航”,只需将响应内容复制到一个在线JSON formatter中,单击wrench图标进行修复,然后单击Format / Beautify

票数 1
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/63831916

复制
相关文章

相似问题

领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档