如何隐藏'pydub‘输出信息？

Question

我的代码

from pydub import generators
from pydub.playback import play

play(generators.Sine(440).to_audio_segment(duration=1500))

在控制台输出中：

Input #0, wav, from '/var/folders/_7/0q83l2vn4zjd7zgqpy3v97840000gn/T/tmphlm6i9s_.wav':
Duration: 00:00:01.50, bitrate: 705 kb/s
Stream #0:0: Audio: pcm_s16le ([1][0][0][0] / 0x0001), 44100 Hz, 1 channels, s16, 705 kb/s

Answer 1

我还没有找到解决方案，但除了"pydub“之外，我还发现了三个替代方案。最后一个是没有输出文本的。(数字-4)

import time
from gtts import gTTS
tts = gTTS('Test', lang='en')
tts.save('Test.mp3')

#=================1
print("1")
from pygame import mixer
mixer.init()
mixer.music.load("Test.mp3") 
mixer.music.play()
time.sleep(1)

#=================2
print("2")
from pydub import AudioSegment
from pydub.playback import play
path_to_file = r"Test.mp3"
song = AudioSegment.from_mp3(path_to_file)
play(song)
time.sleep(1)

#=================3
print("3")
import os
os.system("mpg321 -q Test.mp3")
time.sleep(1)

#=================4
print("4")
from mpyg321.mpyg321 import MPyg321Player
player = MPyg321Player()
player.play_song("Test.mp3")
time.sleep(1)

Answer 2

我的电脑目前有问题，所以我无法检查，但这应该可以工作：

from pydub import generators
from pydub.playback import play
import subprocess, sys

play(generators.Sine(440).to_audio_segment(duration=1500))
if sys.platform in ('linux', 'osx'):
    subprocess.call('clear', shell=True)
elif sys.platform in ('nt', 'dos', 'ce'):
    subprocess.call('cls', shell=True)
else:
    pass

这是一种代码中的“黑客攻击”，每次发送输出时都会清除控制台。像这样的东西可能会起作用，但我仍然无法对其进行测试：

import contextlib
import io

from pydub import generators
from pydub.playback import play

with contextlib.redirect_stdout(io.StringIO()):
    play(generators.Sine(440).to_audio_segment(duration=1500))