我写了一个很大的代码,这需要很长的时间来处理。根据这里的建议,我让它变得更短更好,现在它运行得更快了。然而,我注意到我应该得到值的总和,而我只是得到值。我尝试使用ACCUMULATE TOTAL,但它不起作用,因为LAST-OF只能与BREAK BY一起使用,而我的break by是在QUERY-PREPARE()中。
如何获得以下值的总和?
doc-fiscal.vl-cont-doc
doc-fiscal.vl-bicms
doc-fiscal.vl-icms
doc-fiscal.vl-icmsou
doc-fiscal.vl-ipiou
doc-fiscal.vl-ipiBellow是我正在使用的代码,它几乎工作得很好。
//Query
cQuery = "FOR EACH doc-fiscal WHERE doc-fiscal.dt-docto >= " + QUOTER(pd-data-1) + " AND doc-fiscal.dt-docto <= " + QUOTER(pd-data-2) + " AND (doc-fiscal.cod-observa <> 4 OR doc-fiscal.tipo-nat <> 3) AND doc-fiscal.cd-situacao <> 06 AND doc-fiscal.cd-situacao <> 22".
cQuery = cQuery + semCodEmitente + comCodEmitente + CheckBoxindSitDoc.
cQuery = cQuery + ", EACH natur-oper USE-INDEX natureza WHERE doc-fiscal.nat-operacao = natur-oper.nat-operacao" + modeloEletronico + tipoEntrada + natOper.
cQuery = cQuery + " BREAK BY doc-fiscal.dt-docto BY doc-fiscal.nr-doc-fis ".
QUERY qRelatorio:QUERY-PREPARE(cQuery).
QUERY qRelatorio:QUERY-OPEN().
GET FIRST qRelatorio.
DEF VAR soma-vl-cont-doc AS DECIMAL.
DO WHILE AVAILABLE doc-fiscal:
soma-vl-cont-doc = soma-vl-cont-doc + doc-fiscal.vl-cont-doc.
IF LAST-OF(doc-fiscal.nr-doc-fis) THEN DO:
CREATE tt-relatorio.
ASSIGN
tt-relatorio.nr-doc-fis = doc-fiscal.nr-doc-fis
tt-relatorio.serie = doc-fiscal.serie
tt-relatorio.char-2 = SUBSTRING(doc-fiscal.char-2,155,44, "CHAR")
tt-relatorio.cod-model-nf-eletro = natur-oper.cod-model-nf-eletro
tt-relatorio.tipo = natur-oper.tipo
tt-relatorio.cod-estabel = doc-fiscal.cod-estabel
tt-relatorio.cod-emitente = doc-fiscal.cod-emitente
tt-relatorio.nome-ab-emi = doc-fiscal.nome-ab-emi
tt-relatorio.cgc = doc-fiscal.cgc
tt-relatorio.dt-emis-doc = doc-fiscal.dt-emis-doc
tt-relatorio.dt-docto = doc-fiscal.dt-docto
tt-relatorio.ind-sit-doc = doc-fiscal.ind-sit-doc
tt-relatorio.vl-cont-doc = doc-fiscal.vl-cont-doc
tt-relatorio.vl-bicms = doc-fiscal.vl-bicms
tt-relatorio.vl-icms = doc-fiscal.vl-icms
tt-relatorio.vl-icmsou = doc-fiscal.vl-icmsou
tt-relatorio.vl-ipiou = doc-fiscal.vl-ipiou
tt-relatorio.vl-ipi = doc-fiscal.vl-ipi
tt-relatorio.imp-nota = natur-oper.imp-nota.
GET NEXT qRelatorio.
END.
END.
QUERY qRelatorio:QUERY-CLOSE().谢谢你的帮助,很抱歉我还是个新手。我希望我的问题能帮助其他人。
发布于 2020-12-21 21:43:43
我设法做到了。我使用了LAST-OF()方法。我的代码如下所示。
DEF VAR soma-vl-cont-doc AS DECIMAL. //INICIO DAS SOMAS
DEF VAR soma-vl-bicms AS DECIMAL.
DEF VAR soma-vl-icms AS DECIMAL.
DEF VAR soma-vl-icmsou AS DECIMAL.
DEF VAR soma-vl-ipiou AS DECIMAL.
DEF VAR soma-vl-ipi AS DECIMAL.
DO WHILE AVAILABLE doc-fiscal:
soma-vl-cont-doc = soma-vl-cont-doc + doc-fiscal.vl-cont-doc.
soma-vl-bicms = soma-vl-bicms + doc-fiscal.vl-bicms.
soma-vl-icms = soma-vl-icms + doc-fiscal.vl-icms.
soma-vl-icmsou = soma-vl-icmsou + doc-fiscal.vl-icmsou.
soma-vl-ipiou = soma-vl-ipiou + doc-fiscal.vl-ipiou.
soma-vl-ipi = soma-vl-ipi + doc-fiscal.vl-ipi.
IF QUERY qRelatorio:LAST-OF(2) THEN DO:
CREATE tt-relatorio.
ASSIGN
tt-relatorio.nr-doc-fis = doc-fiscal.nr-doc-fis
tt-relatorio.serie = doc-fiscal.serie
tt-relatorio.char-2 = SUBSTRING(doc-fiscal.char-2,155,44, "CHAR")
tt-relatorio.cod-model-nf-eletro = natur-oper.cod-model-nf-eletro
tt-relatorio.tipo = natur-oper.tipo
tt-relatorio.cod-estabel = doc-fiscal.cod-estabel
tt-relatorio.cod-emitente = doc-fiscal.cod-emitente
tt-relatorio.nome-ab-emi = doc-fiscal.nome-ab-emi
tt-relatorio.cgc = doc-fiscal.cgc
tt-relatorio.dt-emis-doc = doc-fiscal.dt-emis-doc
tt-relatorio.dt-docto = doc-fiscal.dt-docto
tt-relatorio.ind-sit-doc = doc-fiscal.ind-sit-doc
tt-relatorio.vl-cont-doc = soma-vl-cont-doc
tt-relatorio.vl-bicms = soma-vl-bicms
tt-relatorio.vl-icms = soma-vl-icms
tt-relatorio.vl-icmsou = soma-vl-icmsou
tt-relatorio.vl-ipiou = soma-vl-ipiou
tt-relatorio.vl-ipi = soma-vl-ipi
//tt-relatorio.idi-sit-nf-eletro = nota-fiscal.idi-sit-nf-eletro
tt-relatorio.imp-nota = natur-oper.imp-nota.
soma-vl-cont-doc = 0.
soma-vl-bicms = 0.
soma-vl-icms = 0.
soma-vl-icmsou = 0.
soma-vl-ipiou = 0.
soma-vl-ipi = 0.
END.
GET NEXT qRelatorio.
END.有了这个,我设法得到了我想要的答案,并且查询速度很快。如果有任何关于如何让它更快的建议,我愿意接受他们。谢谢。
https://stackoverflow.com/questions/65392713
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