属性的fasterxml序列化

Question

我按照下面的说明使用fasterxml 2.9.4，并尝试将父类中的CurrencyAndAmount类序列化为：

<ParentClass Currency="USD">100000</ParentClass>

但相反，我的情况正在变得更糟。文档表明，isAttribute是我所需要的，但它对我不起作用。我遗漏了什么？提前感谢您在正确方向上的任何指点。

<ParentClass>100000</ParentClass>

依赖关系：

<dependency>
    <groupId>com.fasterxml.jackson.core</groupId>
    <artifactId>jackson-databind</artifactId>
    <version>2.9.4</version>
 </dependency>
 <dependency>
    <groupId>com.fasterxml.jackson.dataformat</groupId>
    <artifactId>jackson-dataformat-xml</artifactId>
    <version>2.9.9</version>
 </dependency>

XmlMapper配置：

mapper.configure(MapperFeature.ACCEPT_CASE_INSENSITIVE_PROPERTIES, true);
mapper.enable(DeserializationFeature.ACCEPT_SINGLE_VALUE_AS_ARRAY);
mapper.setSerializationInclusion(JsonInclude.Include.NON_NULL);
mapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);
AnnotationIntrospector primary = new JacksonAnnotationIntrospector();
AnnotationIntrospector secondary = new JaxbAnnotationIntrospector(TypeFactory.defaultInstance());
mapper.setAnnotationIntrospector(AnnotationIntrospector.pair(primary, secondary));

POJO

public class CurrencyAndAmount {
    @JacksonXmlText
    protected BigDecimal value;
    @JacksonXmlProperty(localName = "Currency", isAttribute = true)
    protected String currency;

    @JsonValue
    public BigDecimal getValue() {
        return value;
    }

    public void setValue(BigDecimal value) {
        this.value = value;
    }

    public String getCurrency() {
        return currency;
    }

    public void setCurrency(String value) {
        this.currency = value;
    }
}

Answer 1

您应该删除JsonValue注释并将您的POJO简化为：

class CurrencyAndAmount {

    @JacksonXmlText
    protected BigDecimal value;

    @JacksonXmlProperty(localName = "Currency", isAttribute = true)
    protected String currency;

    ...
}