我正在运营一个django网站。下面是我的代码:
views.py:
@permission_classes((IsAdminUser,))
class ProfileView(viewsets.ModelViewSet):
queryset=Profile.objects.all()
serializer_class=ProfileSerializer
@csrf_exempt
def list(self,request):
return Response({'message':'Append Profile ID to the API to view Profile of Particular User'})
def get_serializer_class(self):
serializer_class = self.serializer_class
if self.request.method == 'PUT' or self.request.method == 'PATCH':
serializer_class = ProfilesSerializer
return serializer_class
@permission_classes((IsAdminUser,))
class LoginView(viewsets.ModelViewSet):
queryset = Token.objects.all()
serializer_class = LoginSerializer
http_method_names = ['get', 'head']urls.py:
router=routers.DefaultRouter()
router.register('profiles',views.ProfileView)
router.register('login', views.LoginView)
urlpatterns = [
path('home/',include(router.urls)),
]我需要获得JSON格式的响应。如果我在postman中输入url,我会得到这样的错误:“CSRF失败:CSRF cookie未设置。”有人能帮我修复这个错误吗?
发布于 2020-01-06 15:21:25
您可以将此函数放入您的JS文件中并尝试。
function getCookie(name) {
var cookieValue = null;
if (document.cookie && document.cookie != '') {
var cookies = document.cookie.split(';');
for (var i = 0; i < cookies.length; i++) {
var cookie = jQuery.trim(cookies[i]);
// Does this cookie string begin with the name we want?
if (cookie.substring(0, name.length + 1) == (name + '=')) {
cookieValue = decodeURIComponent(cookie.substring(name.length + 1));
break;
}
}
}
return cookieValue;
}
var csrftoken = getCookie('csrftoken');
function csrfSafeMethod(method) {
// these HTTP methods do not require CSRF protection
return (/^(GET|HEAD|OPTIONS|TRACE)$/.test(method));
}
$.ajaxSetup({
beforeSend: function(xhr, settings) {
if (!csrfSafeMethod(settings.type) && !this.crossDomain) {
xhr.setRequestHeader("X-CSRFToken", csrftoken);
}
}
});https://stackoverflow.com/questions/59607906
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