start_workspaces()只接受关键字参数

Question

我正在尝试写一个在Lambda函数中的Python代码，它将在警报触发时启动停止的工作区。响应类型为dict。

但是我得到了错误。下面是我的代码和错误。

import json
import boto3

client = boto3.client('workspaces')
    
def lambda_handler(event, context):
    response = client.describe_workspaces(
        DirectoryId='d-966714f114'
    )
        
    #print(response)
    
    print("hello")

    for i in response['Workspaces']:
        if(i['State']== 'STOPPED'):
            print(i['WorkspaceId'])
            client.start_workspaces(i['WorkspaceId'])

{
    "errorMessage": "start_workspaces() only accepts keyword arguments.",
    "errorType": "TypeError",
    "stackTrace": [
    "  File \"/var/task/lambda_function.py\", line 21, in lambda_handler\n    client.start_workspaces(i)\n",
    "  File \"/var/runtime/botocore/client.py\", line 354, in _api_call\n    raise TypeError(\n"
    ]
}

Answer 1

如果你看一下调用的documentation，它说它需要关键字StartWorkspaceRequests，它本身就是一个字典列表：

{
    'WorkspaceId': 'string'
},

调用不接受参数(只是传递一个没有对应关键字的值)。您需要调整您的调用以符合boto3期望的格式。

import json
import boto3

client = boto3.client('workspaces')
    
def lambda_handler(event, context):
    response = client.describe_workspaces(
        DirectoryId='d-966714f114'
    )
        
    workspaces_to_start = []
         
    for i in response['Workspaces']:
        if(i['State']== 'STOPPED'):
            workspaces_to_start.append({'WorkspaceId': i['WorkspaceId']})

    if workspaces_to_start:
        client.start_workspaces(StartWorkspaceRequests=workspaces_to_start)