如果输入与web请求输出中的任何字符串匹配，则返回true

Question

如果const ip_address (string)存在于const request的输出中，我需要下面的代码来返回true。

function getBlocklist() {
    const baseurl = "https://raw.githubusercontent.com/firehol/blocklist-ipsets/master/bi_sip_0_1d.ipset"
    const request = require('request');
    request(baseurl, function (error, response, body){
        if (!error && response.statusCode == 200) {
            console.log(body)
        }
    })
}
getBlocklist()

Answer 1

将请求部分转换为promise，并检查您要查找的变量是否存在。

async function getBlocklist() {
        const baseurl = "https://raw.githubusercontent.com/firehol/blocklist-ipsets/master/bi_sip_0_1d.ipset"
        const request = require('request');
    
        const IssueRequest = ()=>{
          return new promise ((resolve)=>{
                request(baseurl, function (error, response, body){
                    if (!error && response.statusCode == 200) {
                        if (body.output.ip_address){
                             resolve(true);
                       }else{
                         resolve(false);
                       }
                    }
                })
            
            });
        }
      return await IssueRequest();
    }