Blender -使用bpy插入文本按钮

Question

我正在为Blender 2.80插件设计一个简单的GUI。我已经创建了一个对话框来输入一些数据：

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我想替换文本行("Lorem ipsum ...")带有自定义标签的按钮(例如“单击此处访问我们的网站”)。

下面是我使用的代码：

class ExportFDSCloudHPC(Operator):

    bl_idname = "..."
    bl_label = "Title"
    bl_description = "..."

    data1 = bpy.props.StringProperty(
        name = "Text 1",
        default = "..."
    )

    data2 = bpy.props.StringProperty(
        name = "Text 2",
        default = "..."
    )

    data3 = bpy.props.StringProperty(
        name = "Text 3",
        default = "..."
    )
    
    def draw(self, context):
        col = self.layout.column(align = True)
        col.prop(self, "data1")

        self.layout.label(text="Lorem ipsum dolor sit amet, consectetur adipisci elit...")

        col = self.layout.column(align = True)
        col.prop(self, "data2")

        col = self.layout.column(align = True)
        col.prop(self, "data3")

    def execute(self, context):
        ...

Answer 1

要获取按钮，您需要提供一个现有的操作符：row.operator("wm.save_as_mainfile")按钮文本在operator中定义。如果要更改现有操作员名称，请使用row.operator("wm.save_as_mainfile", text='My Save Label')

您可以创建自己的运算符：

import bpy

def main(context):
    for ob in context.scene.objects:
        print(ob)

class SimpleOperator(bpy.types.Operator):
    """Tooltip"""
    bl_idname = "object.simple_operator" # <- put this string in layout.operator()
    bl_label = "Simple Object Operator" # <- button name

    @classmethod
    def poll(cls, context):
        return context.active_object is not None

    def execute(self, context):
        main(context)
        return {'FINISHED'}

def register():
    bpy.utils.register_class(SimpleOperator)

def unregister():
    bpy.utils.unregister_class(SimpleOperator)
    
if __name__ == "__main__":
    register()

    # test call
    bpy.ops.object.simple_operator()

然后像这样使用它：

[..]
col.prop(self, "data1")
col.operator("object.simple_operator")
# self.layout.label(text="Lorem ipsum dolor sit amet, consectetur adipisci elit...")

col = self.layout.column(align = True)
[..]