java.lang.NoSuchMethodException: Practice.Virual.main [class [Ljava.lang.String;] at java.lang.Class.getMethod(Class.java:2072)错误

Question

我的代码出了什么问题？我是编程新手，所以即使我的代码可以运行，我在这里也可能会遇到一些问题。不过，我的代码似乎没有运行。显示的错误是粘贴在这篇文章的底部。

String name, streetname, barangay, city, region;
int zipcode, streetno;

   void display() {
     System.out.println("Name: " + this.name);
     System.out.println("Street No: " + this.streetno);
     System.out.println("Street: " + this.streetname);
     System.out.println("Barangay: " + this.barangay);
     System.out.println("City : " + this.city);
     System.out.println("Region: " + this.region);
     System.out.println("Zip Code : " + this.zipcode);
     
   }
}

class residentinfo {

  public static void main(String[] args) {
  
  Scanner in = new Scanner(System.in);
  Virual rsd = new Virual();
  
  System.out.println("Enter Name: ");
  rsd.name = in.nextLine();
  System.out.println("Enter Street No: ");
  rsd.streetno = in.nextInt();
  System.out.println("Enter Street Name: ");
  rsd.streetname = in.nextLine();
  System.out.println("Enter Barangay: ");
  rsd.barangay = in.nextLine();
  System.out.println("Enter City: ");
  rsd.city = in.nextLine();
  System.out.println("Enter Region: ");
  rsd.region = in.nextLine();
  System.out.println("Enter Zip Code: ");
  rsd.zipcode = in.nextInt();
  
  rsd.display();

  }
}

我的代码出了什么问题？当我运行它的时候，这个错误出现了。我的代码似乎没有运行，但它已经运行了。

java.lang.NoSuchMethodException: Practice.Virual.main [class [Ljava.lang.String;] at java.lang.Class.getMethod(Class.java:2072)
at java.lang.Class.getDeclaredMethod(Class.java:2050)
at com.duy.android.compiler.java.Java.run(Java.java:105)
at com.duy.ide.javaide.run.activities.ExecuteActivity.executeDex(ExecuteActivity.java:147)
at com.duy.ide.javaide.run.activities.ExecuteActivity.exec(ExecuteActivity.java:124)
at com.duy.ide.javaide.run.activities.ExecuteActivity.access$100(ExecuteActivity.java:45)
at com.duy.ide.javaide.run.activities.ExecuteActivity$1.run(ExecuteActivity.java:88)
at java.lang.Thread.run(Thread.java:923

Answer 1

有几件事你应该用你的代码来修复。一般来说，Java中的类名都是以大写字母开头的。您应该为您的变量使用getter和setter，以获得最佳实践。此外，您不能使用当前代码读取streetName，因为当您调用in.nextInt()方法时，它不会使用换行符。此外，为了获得最佳实践，您应该使用camelCase作为变量名。

这里有一个更好的方法来处理你的代码。

public class Virual {
    private String name;
    private String streetName;
    private String barangay;
    private String city;
    private String region;
    private int zipcode;
    private int streetNo;

    public Virual() {
    }

    @Override
    public String toString() {
        return String.format("Name: %s Street No: %d Street: %s Barangay: %s City : %s Region: %s Zip Code : %d", name, streetNo, streetName, barangay, city, region, zipcode);
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public String getStreetName() {
        return streetName;
    }

    public void setStreetName(String streetName) {
        this.streetName = streetName;
    }

    public String getBarangay() {
        return barangay;
    }

    public void setBarangay(String barangay) {
        this.barangay = barangay;
    }

    public String getCity() {
        return city;
    }

    public void setCity(String city) {
        this.city = city;
    }

    public String getRegion() {
        return region;
    }

    public void setRegion(String region) {
        this.region = region;
    }

    public int getZipcode() {
        return zipcode;
    }

    public void setZipcode(int zipcode) {
        this.zipcode = zipcode;
    }

    public int getStreetNo() {
        return streetNo;
    }

    public void setStreetNo(int streetNo) {
        this.streetNo = streetNo;
    }
}


public class ResidentInfo {
    public static void main(String[] args) {

        Scanner in = new Scanner(System.in);
        Virual rsd = new Virual();

        System.out.println("Enter Name: ");
        rsd.setName(in.nextLine());
        System.out.println("Enter Street No: ");
        rsd.setStreetNo(in.nextInt());
        in.nextLine(); //to consume /n character (new line)
        /*if you don't put in.nextLine after in.nextInt , in.nextInt method don't read newline char
        so you can't enter value for street name
         */
        System.out.println("Enter Street Name: ");
        rsd.setStreetName(in.nextLine());
        System.out.println("Enter Barangay: ");
        rsd.setBarangay(in.nextLine());
        System.out.println("Enter City: ");
        rsd.setCity(in.nextLine());
        System.out.println("Enter Region: ");
        rsd.setRegion(in.nextLine());
        System.out.println("Enter Zip Code: ");
        rsd.setZipcode(in.nextInt());

        System.out.println(rsd.toString());

    }
}