我有一个查询,它显示了过去5分钟内5xx和4xx错误的结果:
requests
| where timestamp > now() - 5m
| where url contains "xxxxxx" and resultCode startswith "5" or resultCode startswith "4"
| project resultCode
| summarize Count= count() by resultCode查询打印所有5xx和4xx,如下所示:

是否可以获得所有4xx和5xx的计数,但打印在2行??示例:

谢谢
发布于 2021-09-30 17:30:13
像这样的东西应该能起到作用
datatable(resultCode: string, count: long) [
400, 97,
401, 764,
403, 6118,
404, 7083,
406, 11,
500, 131
]
| extend resultKind= strcat(substring(resultCode, 0, 1), "xx")
| summarize sum(['count']) by resultKindhttps://stackoverflow.com/questions/69396360
复制相似问题