我是bull的新手,我已经尝试过基于他们的文档代码运行公牛。进程正在启动,但是我的任务没有完成,或者不确定它是否触发了complete事件?我不确定我哪里弄错了
将我的代码附加到下面
const Queue = require('bull');
const myFirstQueue = new Queue('my-first-queue',
{
redis: {
port: Config.redis.port,
host: Config.redis.host,
password: Config.redis.password
},
});
(async function ad() {
const job = await myFirstQueue.add({
foo: 'bar',
});
})();
myFirstQueue.process(async (job, data) => {
log.debug({ job, data }, 'Job data');
let progress = 0;
for (let i = 0; i < 10; i++) {
await doSomething(data);
progress += 10;
job.progress(progress).catch(err => {
log.debug({ err }, 'Job progress err');
});
log.debug({ progress }, 'After await');
}
return job;
});
const doSomething = data => {
return new Promise((resolve, reject) => {
return resolve(data);
});
};
myFirstQueue.on('completed', (job, result) => {
log.debug(`Job completed with result ${job}`);
});
myFirstQueue.on('progress', (job, progress) => {
log.debug(`Job progress with result ${job} ${progress}`);
});我可以看到日志,它在进度事件处理程序中,但是完成事件没有被触发。任何帮助我们都将不胜感激
发布于 2019-06-18 12:54:13
您需要从process调用done(),然后只会触发已完成的事件。
myFirstQueue.process(async (job, done) => {
const data = job.data;
let progress = 0;
for (let i = 0; i < 10; i++) {
await doSomething(data);
progress += 10;
job.progress(progress).catch(err => {
log.debug({ err }, 'Job progress err');
});
}
done();
});发布于 2019-10-09 22:21:32
您可以从作业对象本身获取数据,不需要向外部传递数据,处理回调需要job和data()作为参数。最后调用data()回调完成一个任务。您可以传递数据,如果某些验证失败,还可以传递错误。更好地解释https://github.com/OptimalBits/bull/blob/develop/REFERENCE.md#queueprocess
// call done when finished
done();
// or give a error if error
done(new Error('error transcoding'));
// or pass it a result
done(null, { framerate: 29.5 /* etc... */ });如果不想调用done()回调,可以直接使用promise,ref-https://github.com/OptimalBits/bull#using-promises
对你的代码做了一些小的修改,希望它能有所帮助。
const Queue = require('bull');
const myFirstQueue = new Queue('my-first-queue');
(async function ad() {
const job = await myFirstQueue.add({
foo: 'bar',
});
})();
myFirstQueue.process(async (job, done) => {
log.debug( 'Job data ' + job.data);
let progress = 0;
for (let i = 0; i < 10; i++) {
await doSomething(job.data);
progress += 10;
job.progress(progress).catch(err => {
log.debug({ err }, 'Job progress err');
});
log.debug({ progress }, 'After await');
}
done(null, {done: job.data}); //we need this if we are not using promise
});
const doSomething = data => {
return new Promise((resolve, reject) => {
return resolve(data);
});
};
myFirstQueue.on('completed', (job, result) => {
log.debug(`Job completed with result ${job}`);
});
myFirstQueue.on('progress', (job, progress) => {
log.debug(`Job progress with result ${job} ${progress}`);
});https://stackoverflow.com/questions/56256609
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