在电路板中插入数组

Question

我试着用这段代码把一个数组"a“放到这个线路板上，但是我只得到了一个只有数组第一个数字的线路板，似乎在变量"i”上缺少并递增，但是我不能在join附近没有语法错误的情况下放入递增，有人能帮忙吗？提前谢谢。代码如下：

`a = [25, 24, 23, 22, 21, 20, 19, 18, 17, 16, 15, 14, 13, 12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1]

i = 0


def inc_i(i):
    i += 1
    return i

def board_draw(height, width, i):
    top = "┌" + "┬".join(["─"*6]*width) + "┐\n"
    bottom = "└" + "┴".join(["─"*6]*width) + "┘"
    middle = "├" + "┼".join(["─"*6]*width) + "┤\n"
    print(top +
          middle.join(
              "│" +
              "│".join('  {:02d}  '.format(a[i])
                       for y in range(width)) +
              "│\n"

              for x in range(height)) +

          bottom)

board_draw(5, 5, 0)`

​

​

我要数组中的每个单元格都有一个不同的数字。

提前感谢

Answer 1

I在任何时候都不会递增。为了让你的程序保持“逻辑性”，试试这个：

a = [25, 24, 23, 22, 21, 20, 19, 18, 17, 16, 15, 14, 13, 12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1]

def board_draw(height, width):
    top = "┌" + "┬".join(["─"*6]*width) + "┐\n"
    bottom = "└" + "┴".join(["─"*6]*width) + "┘"
    middle = "├" + "┼".join(["─"*6]*width) + "┤\n"
    print(top +
          middle.join(
              "│" +
              "│".join('  {:02d}  '.format(a[(x*width) + y]) for y in range(width)) +
              "│\n" for x in range(height)) +
              bottom
          )

board_draw(5, 5)

Answer 2

这是你想要的结果吗？

a = [[25, 24, 23, 22, 21], [20, 19, 18, 17, 16], [15, 14, 13, 12, 11], [10, 9, 8, 7, 6], [5, 4, 3, 2, 1]]

i = 0

def inc_i(i):
    i += 1
    return i


def board_draw(height, width, i):
    top = "┌" + "┬".join(["─"*6]*width) + "┐\n"
    bottom = "└" + "┴".join(["─"*6]*width) + "┘"
    middle = "├" + "┼".join(["─"*6]*width) + "┤\n"
    print(top +
          middle.join(
              "│" +
              "│".join('  {:02d}  '.format(a[x][y])
                       for y in range(width)) +
              "│\n"

              for x in range(height)) +

          bottom)


board_draw(5, 5, 0)

​

​

您可能希望转换列表a，如下所示：

a = [25, 24, 23, 22, 21, 20, 19, 18, 17, 16, 15, 14, 13, 12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1]

a_bis = [[n for n in a[i:i+4]] for i in range(5)]
a_bis

[[25, 24, 23, 22],
 [24, 23, 22, 21],
 [23, 22, 21, 20],
 [22, 21, 20, 19],
 [21, 20, 19, 18]]

Answer 3

我修改并使用了您已经定义的函数inc_i()来迭代列表并打印出正确的结果：

a = [25, 24, 23, 22, 21, 20, 19, 18, 17, 16, 15, 14, 13, 12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1]

i = -1
def inc_i():
    global i
    i += 1
    return i

def board_draw(height, width, i):
    top = "┌" + "┬".join(["─"*6]*width) + "┐\n"
    bottom = "└" + "┴".join(["─"*6]*width) + "┘"
    middle = "├" + "┼".join(["─"*6]*width) + "┤\n"
    print(top +
          middle.join(
              "│" +
              "│".join('  {:02d}  '.format(a[inc_i()]) for y in range(width)) +
              "│\n" for x in range(height)) +
          bottom)

board_draw(5, 5, 0)