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在python中获取RSI
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Stack Overflow用户
提问于 2021-01-15 06:26:21
回答 1查看 368关注 0票数 2

我一直在尝试计算股票的14 RSI,我设法让它工作,在某种程度上,它给出了不准确的数字

代码语言:javascript
复制
import pandas as pd 
import datetime as dt
import pandas_datareader as web

ticker = 'TSLA'

start = dt.datetime(2018, 1, 1)
end = dt.datetime.now()

data = web.DataReader(ticker, 'yahoo', start, end)

delta = data['Adj Close'].diff(1)
delta.dropna(inplace=True)

positive = delta.copy()
negative = delta.copy()

positive[positive < 0] = 0
negative[negative > 0] = 0

days = 14

average_gain = positive.rolling(window=days).mean()
average_loss = abs(negative.rolling(window=days).mean())

relative_strenght = average_gain / average_loss
rsi = 100.0 - (100.0 / (1.0 + relative_strenght))
print(ticker + str(rsi))

它最终给了我77.991564 (14天RSI),而我应该得到70.13 (14天RSI),有人知道我做错了什么吗?

还有,是的,我读过Calculating RSI in Python,但它并不能帮助我满足我的需求

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回答 1

Stack Overflow用户

发布于 2021-01-29 05:45:43

这里有一种自己计算RSI的方法。代码可以优化,但我更喜欢让它更容易理解,让你优化。

对于这个例子,我们假设您有一个名为df的DataFrame,它有一个名为' close‘的列,用于表示收盘价。顺便说一句,请注意,例如,如果您将RSI的结果与一个工作站进行比较,则应确保比较的值相同。例如,如果在车站,你的出价接近,而你在mid或ask上自己计算,结果就不一样了。

让我们看看代码:

代码语言:javascript
复制
def rsi(df,_window=14,_plot=0,_start=None,_end=None):
    """[RSI function]

    Args:
        df ([DataFrame]): [DataFrame with a column 'Close' for the close price]
        _window ([int]): [The lookback window.](default : {14})
        _plot ([int]): [1 if you want to see the plot](default : {0})
        _start ([Date]):[if _plot=1, start of plot](default : {None})
        _end ([Date]):[if _plot=1, end of plot](default : {None})
    """    

    ##### Diff for the différences between last close and now
    df['Diff'] = df['Close'].transform(lambda x: x.diff())
    ##### In 'Up', just keep the positive values
    df['Up'] = df['Diff']
    df.loc[(df['Up']<0), 'Up'] = 0
    ##### Diff for the différences between last close and now
    df['Down'] = df['Diff']
    ##### In 'Down', just keep the negative values
    df.loc[(df['Down']>0), 'Down'] = 0 
    df['Down'] = abs(df['Down'])

    ##### Moving average on Up & Down
    df['avg_up'+str(_window)] = df['Up'].transform(lambda x: x.rolling(window=_window).mean())
    df['avg_down'+str(_window)] = df['Down'].transform(lambda x: x.rolling(window=_window).mean())

    ##### RS is the ratio of the means of Up & Down
    df['RS_'+str(_window)] = df['avg_up'+str(_window)] / df['avg_down'+str(_window)]

    ##### RSI Calculation
    ##### 100 - (100/(1 + RS))
    df['RSI_'+str(_window)] = 100 - (100/(1+df['RS_'+str(_fast)]))

    ##### Drop useless columns
    df = df.drop(['Diff','Up','Down','avg_up'+str(_window),'avg_down'+str(_window),'RS_'+str(_window)],axis=1)

    ##### If asked, plot it!
    if _plot == 1:
        sns.set()
        fig = plt.figure(facecolor = 'white', figsize = (30,5))
        ax0 = plt.subplot2grid((6,4), (1,0), rowspan=4, colspan=4)
        ax0.plot(df[(df.index<=end)&(df.index>=start)&(df.Symbol==_ticker.replace('/',''))]['Close'])
        ax0.set_facecolor('ghostwhite')
        ax0.legend(['Close'],ncol=3, loc = 'upper left', fontsize = 15)
        plt.title(_ticker+" Close from "+str(start)+' to '+str(end), fontsize = 20)

        ax1 = plt.subplot2grid((6,4), (5,0), rowspan=1, colspan=4, sharex = ax0)
        ax1.plot(df[(df.index<=end)&(df.index>=start)&(df.Symbol==_ticker.replace('/',''))]['RSI_'+str(_window)], color = 'blue')
        ax1.legend(['RSI_'+str(_window)],ncol=3, loc = 'upper left', fontsize = 12)
        ax1.set_facecolor('silver')
        plt.subplots_adjust(left=.09, bottom=.09, right=1, top=.95, wspace=.20, hspace=0)
        plt.show()
    return(df)

要调用该函数,您只需键入

代码语言:javascript
复制
df = rsi(df)

如果您将其保留为默认值,或者更改参数的_window和/或_plot。请注意,如果输入_plot=1,则需要向绘图的开始和结束提供字符串或日期时间。

票数 0
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/65727800

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