我正在尝试定义一个总是成功的关系callto_status(Goal, Status),并根据调用Goal的结果统一状态(换句话说,我想实现call_with_inference_limit/3的一个具体化版本)。我的实现使用的是SWI的call_with_inference_limit/3,它具有与call_with_time_limit/3相同的接口(这应该也能使它在这种情况下工作)。call_with_..._limit的实现不会走回头路,所以我认为最好不要给人一种报告替代目标的答案的印象。
为了提高可读性,我引入了辅助谓词derivable_st。它处理成功和超时的情况,否则会失败。
% if Goal succeeds, succeed with Status = true,
% if Goal times out, succeed with Status = timeout
% if Goal fails, fail
derivable_st(Goal, Status) :-
T = 10000, % set inference limit
% copy_term(Goal, G), % work on a copy of Goal, we don't want to report an answer substitution
call_with_inference_limit(G, T, R), % actual call to set inference limit
( R == !
-> Status = true % succeed deterministically, status = true
; R == true
-> Status = true % succeed non-deterministically, status = true
; ( R == inference_limit_exceeded % timeout
-> (
!, % make sure we do not backtrack after timeout
Status = timeout % status = timeout
)
; throw(unhandled_case) % this should never happen
)
).主谓词包装在derivable_st周围,并处理失败情况和可能抛出的异常(如果有)。我们可能想要挑出堆栈溢出(在推理限制太高的情况下发生),但现在我们只报告任何异常。
% if Goal succeeds, succeed with Status = true,
% if Goal times out, succeed with Status = timeout
% if Goal fails, succeed with Status = false
% if Goal throws an error, succeed with Status = exception(The_Exception)
% Goal must be sufficiently instantiated for call(Goal) but will stay unchanged
callto_status(Goal, Status) :-
catch(( derivable_st(Goal, S) % try to derive Goal
-> Status = S % in case of success / timeout, pass status on
; Status = false % in case of failure, pass failure status on, but succeed
),
Exception,
Status = exception(Exception) % wrap the exception into a status term
).该谓词适用于一些简单的测试用例:
?- callto_reif( length(N,X), Status).
Status = true.
?- callto_reif( false, Status).
Status = false.
?- callto_reif( (length(N,X), false), Status).
Status = timeout.我现在的问题有点模糊:这个谓词是否如我所说的那样做?你看到任何错误/改进点了吗?我非常感谢您的任何意见!
编辑:根据@false的建议,注释掉了copy_term/2
发布于 2019-07-27 20:57:15
这是一个较短的解决方案:
callto_status(Goal, Status) :-
call_with_inference_limit(Goal, 10000, Status0),
(Status0 = ! -> !, Status = true; Status = Status0).
callto_status(_, false).你看到原来的有多有用了吧!状态是为了避免不必要的选择点:
?- callto_status(member(X,[1,2,3]), Y).
X = 1,
Y = true
X = 2,
Y = true
X = 3,
Y = true.
?- callto_status(fail, Y).
Y = false.当然,您也可以仅将Status0 = ! -> !, Status = true替换为Status0 = ! -> Status = true。然后,您将始终获得剩余的选择点:
?- callto_status(member(X,[1,2,3]), Y).
X = 1,
Y = true
X = 2,
Y = true
X = 3,
Y = true
Y = false.从这个问题看,你到底想要什么并不清楚。
https://stackoverflow.com/questions/54678295
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