我刚刚开始使用Minizinc,如果我能为我的问题建立一个模型,我会很感激。
我有三样东西。在购买每一件商品时,我都会得到一定的返现奖金,而且购买一件商品的次数是有限制的。另外,我的购物车里也有空位。
示例:
items = [ 'i1', 'i2', 'i3' ]
cart_capacity = 7
cashback = [30,10,20]
(meaning, with purchase of item1 I get back $30)
Frequency_of_purchase = [ 2 , 1 , 5]
(meaning, item 3 can be purchased 5 times)我需要一个输出,告诉我每件商品可以购买多少次,这样我就可以获得最大的现金回扣
Desired result = { i1 : 2, i2: 0, i3 : 5}发布于 2021-04-17 07:02:57
通常我们会说字符串输入主要是作为不同项目的标签。
在MiniZinc中,最好的方法是使用枚举类型。枚举类型既可用作数组的索引,也可用作变量的可能值。
您的模型可以表示为:
/* --- Problem Parameters --- */
enum ITEMS;
int: cart_capacity;
array[ITEMS] of int: cash_back;
array[ITEMS] of int: item_capacity;
/* --- Decision Variables --- */
array[ITEMS] of var 0..ub_array(item_capacity): purchases;
/* --- Constraints --- */
constraint forall(it in ITEMS) (purchases[it] < item_capacity[it]);
constraint sum(it in ITEMS) (purchases[it]) < cart_capacity;
/* --- Solving Goal --- */
solve maximize sum(it in ITEMS) (purchases[it]*cash_back[it]);
output ["{"] ++ [show(it) ++ ": " ++ show(purchases[it]) ++ if it == max(ITEMS) then "" else ", " endif | it in ITEMS] ++ ["}"];您的问题中的输入必须稍微调整为:
ITEMS = { 'i1', 'i2', 'i3' };
cart_capacity = 7;
cashback = [30, 10, 20];
item_capacity = [2 , 1 , 5];https://stackoverflow.com/questions/67132861
复制相似问题