Numpy.float64的对象在auc中不可调用(召回，精度)

Question

当我运行以下命令时程序抛出['numpy.float64' object is not callable]错误：

auc(recall, precision)

直到今天，我才成功地运行了这个程序。我很感激在这方面的任何帮助，谢谢！我也用()试过了，但不起作用。

fit_logreg = LogisticRegression(class_weight='balanced', verbose=0)

fit_logreg.set_params(penalty = 'l2',
                  C = 0.00001, 
                  n_jobs=-1,
                  verbose=0
                  )
###########################################################
###4#TRAIN THE FITTING MODEL ON THE TRAINING DATASET###
###########################################################
# fit a model
fit_logreg.fit(trainX, trainy)

# score the test dataset

predictions_logreg = fit_logreg.predict(testX)
#predictions_logreg = predictions_logreg.values.ravel() 

###########################################################
###5#OOB ERROR AND CLASSIFICATION SUCCESS METRICS###
###########################################################

##ROC AUC SCORE
roc_auc_score(testy, predictions_logreg,average='macro')

##RECALL-PRECISION CURVE

# predict probabilities
probs = fit_logreg.predict_proba(testX)
# keep probabilities for the positive outcome only
probs = probs[:, 1]
# predict class values
yhat = predictions_logreg
# calculate precision-recall curve
precision, recall, thresholds = precision_recall_curve(testy, probs)
# calculate F1 score
f1 = f1_score(testy, yhat)

# calculate precision-recall AUC
auc(recall, precision)

这是我得到的错误：

TypeErrorTraceback (most recent call last)
<ipython-input-1-74f87a22f33a> in <module>()
     68 # calculate precision-recall AUC
     69 #auc = auc(recall, precision)
---> 70 auc(recall, precision)

TypeError: 'numpy.float64' object is not callable

Answer 1

当您运行以下代码行时(在回溯中注释掉)：

auc = auc(recall, precision)

您将名称空间中的函数auc替换为numpy对象。再次调用auc会抛出错误。

Answer 2

您可以按如下方式对此问题进行分类：

from sklearn import metrics

metrics.auc(recall, precision)

Answer 3

您应该使用print(auc(recall, precision))