我正在使用一个slimselectjs多选插件,并有一个HTML表单提交给它,以便添加选定的选项值。但是,当通过表单添加所选的选项值时,如果我输入相同的文本和标签,则可能会创建重复的值。此外,如果我只单击“添加”,它将添加一个没有“食品名称”的条目。
例如,我在输入框中输入"tacos“,在下拉列表中选择”食物“,然后点击”添加“并重复3次,然后我将得到4个相同的条目-”食物: tacos“。
如果我只点击“添加”,它将只输入“食物:”,分号后面没有任何东西。
如何防止这两种情况的发生?如何防止1.重复条目2.空白/不完整的提交被添加?
<script src="https://cdnjs.cloudflare.com/ajax/libs/slim-select/1.26.0/slimselect.min.js"></script>
<link href="https://cdnjs.cloudflare.com/ajax/libs/slim-select/1.26.0/slimselect.min.css" rel="stylesheet"></link>
<select id="multiple" multiple>
<option value="value 1">drinks: lemonade</option>
<option value="value 2">food: hot dog</option>
<option value="value 3" selected>food: mac & cheese</option>
<option value="value 4">food: pizza</option>
<option value="value 8" selected>supplements: vitamin e</option>
</select>
<br><br>
<form>
<label for="fname">food name:</label>
<input type="text" id="fname" name="fname"><br><br>
<label for="type">Choose a label:</label>
<select name="type" id="type">
<option value="value 5">food</option>
<option value="value 6">drinks</option>
<option value="value 25">drugs</option>
<option value="value 50">supplements</option>
</select><br><br>
<input type="submit" value="Add">
</form>
<script type="text/javascript">
new SlimSelect({
select: '#multiple'
});
const btnAdd = document.querySelector('input[type="submit"]');
btnAdd.addEventListener('click', function(e) {
e.preventDefault();
let input = document.querySelector('#fname');
let select = document.querySelector('#type');
let selectOptions = document.querySelectorAll('#type > option');
let selectMultiple = document.querySelector('#multiple');
// create option element
let option = document.createElement('option');
let optionContent = selectOptions[select.selectedIndex].textContent+':'+input.value;
option.value = optionContent;
option.textContent = optionContent;
option.setAttribute('selected', '');
// insert in select multiple
selectMultiple.appendChild(option);
// reset input and select
input.value = '';
select.selectedIndex = 0;
})
</script>发布于 2020-07-09 13:58:39
您可以使用.innerHTML而不是费力地构建option元素来简化脚本。我还通过删除它们的value属性来简化您的type.options。您只需在脚本中引用它们的文本值。当您省略value属性时,选项文本将自动成为该选项的value。
我让您清除输入字段的值,因为您不想接受任何重复,但我保留了当前选择的type,以便用户在想要输入另一个相同类型的项时更容易。
另外:您的代码中没有jQuery,所以我删除了这个标记。
new SlimSelect({ select: '#multiple' });
let mul=document.querySelector('#multiple');
document.querySelector('#add').addEventListener('click', function(e) {
e.preventDefault();
let inp=document.querySelector('#fname'), foodName=inp.value.trim();
if (foodName) {
let newval = document.querySelector('#type').value+': '+foodName;
// create option element and insert it in select multiple:
if ([...mul.children].every(o=>o.textContent!=newval))
mul.innerHTML+=`<option selected>${newval}</option>`;
// reset input:
inp.value = '';
}
});<script src="https://cdnjs.cloudflare.com/ajax/libs/slim-select/1.26.0/slimselect.min.js"></script>
<link href="https://cdnjs.cloudflare.com/ajax/libs/slim-select/1.26.0/slimselect.min.css" rel="stylesheet"></link>
<select id="multiple" multiple>
<option value="value 1">drinks: lemonade</option>
<option value="value 2">food: hot dog</option>
<option value="value 3" selected>food: mac & cheese</option>
<option value="value 4">food: pizza</option>
<option value="value 8" selected>supplements: vitamin e</option>
</select>
<br><br>
<form>
<label for="fname">food name:</label>
<input type="text" id="fname" name="fname"><br><br>
<label for="type">Choose a label:</label>
<select name="type" id="type">
<option>food</option>
<option>drinks</option>
<option>drugs</option>
<option>supplements</option>
</select><br><br>
<button id="add">Add</button>
</form>
该操作的主要部分在
if ([...mul.children].every(o=>o.textContent!=newval))
mul.innerHTML+=`<option selected>${newval}</option>`;我首先断言在multiple select中没有文本内容等于newval的其他选项,然后才会附加一个包含该文本和值的选项。
发布于 2020-07-09 14:03:01
我没有看到问题#1中提到的任何重复项。我为fname添加了一个验证点,以确保它不为空
new SlimSelect({
select: '#multiple'
});
const btnAdd = document.querySelector('input[type="submit"]');
btnAdd.addEventListener('click', function(e) {
e.preventDefault();
let input = document.querySelector('#fname');
let select = document.querySelector('#type');
let selectOptions = document.querySelectorAll('#type > option');
let selectMultiple = document.querySelector('#multiple');
// validate food name field
if (!input.value || input.value == ' '){
alert('Please Enter Food Name')
return
}
// create option element
let option = document.createElement('option');
let optionContent = selectOptions[select.selectedIndex].textContent+':'+input.value;
option.value = optionContent;
option.textContent = optionContent;
option.setAttribute('selected', '');
// insert in select multiple
selectMultiple.appendChild(option);
// reset input and select
input.value = '';
select.selectedIndex = 0;
})<script src="https://cdnjs.cloudflare.com/ajax/libs/slim-select/1.26.0/slimselect.min.js"></script>
<link href="https://cdnjs.cloudflare.com/ajax/libs/slim-select/1.26.0/slimselect.min.css" rel="stylesheet"></link>
<select id="multiple" multiple>
<option value="value 1">drinks: lemonade</option>
<option value="value 2">food: hot dog</option>
<option value="value 3" selected>food: mac & cheese</option>
<option value="value 4">food: pizza</option>
<option value="value 8" selected>supplements: vitamin e</option>
</select>
<br><br>
<form>
<label for="fname">food name:</label>
<input type="text" id="fname" name="fname"><br><br>
<label for="type">Choose a label:</label>
<select name="type" id="type">
<option value="value 5">food</option>
<option value="value 6">drinks</option>
<option value="value 25">drugs</option>
<option value="value 50">supplements</option>
</select><br><br>
<input type="submit" value="Add">
</form>
https://stackoverflow.com/questions/62807910
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