替换set_fact中的值

Question

下面是我的样例yaml文件

student:
  faculty: "Information Technology"
  code: "FC1412"
  abraham:
    country: "UK"
    age: "56"
  aaron:
    country: "UK"
    age: "56"
  chin:
    country: "UK"
    age: "56"

下面是我的Ansible代码

- slurp:
    src: {{ yaml_file_directory }}
  register: registerValue

- debug:
    msg: {{ registerValue['content'] | b64decode | from_yaml }}

它将给出如下输出

student: {
  faculty: "Information Technology",
  code: "FC1412",
  abraham: {
    country: "UK",
    age: "56"
  },
  aaron:
    country: "UK",
    age: "56",
  },
  jamess: {
    country: "UK",
    age: "56"
  }
}

是否有可能替换像aaron这样的值，从56岁到57岁。我希望你们能给我一些建议

Answer 1

字典在Ansible中是不可变的。你必须改写整个字典。例如，将更新放入字典中

        update:
          aaron:
            age: "57"

并使用filter combine。设置recusive=True以保留所有属性

    - set_fact:
        student: "{{ student|combine(update, recursive=True) }}"
      vars:
        update:
          aaron:
            age: "57"

给出

  student:
    aaron:
      age: '57'
      country: UK
    abraham:
      age: '56'
      country: UK
    code: FC1412
    faculty: Information Technology
    jamess:
      age: '56'
      country: UK