如何将int类型的指针复制到结构数组内的uint8_t数组中？

Question

我正在编写一个程序，它将读取文件并将值保存在数组中。这是我的文件：

communication1 : b8:27:eb:cf:54:2c, b8:27:eb:75:85:e4, 2000000;
communication2 : mm:27:eb:cf:54:2c, xx:27:eb:75:85:e4, 2200000;

这是我的代码：

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <stdint.h>

struct mac{
        uint8_t address_bytes [6];
};

void main(){
    int count = 2, i = 0;
    char *Trash[4], *Time[4];
    int k=0;
    int mac1[6], mac2[6];
    char tempbuff[100];
    char trash[20], mac_s[20], mac_d[20], time[20];
    struct mac Mac1[2], Mac2[2];
    int j = 0;

    FILE *fptr =  fopen("config", "r");
    fseek(fptr, 0, SEEK_SET);
    while(!feof(fptr)){
       if (fgets(tempbuff,100,fptr)) {
               printf("\n%s", tempbuff);
               sscanf(tempbuff, "%15s : %17[^;], %17[^;], %17[^;];", trash, mac_s, mac_d, time);
                Trash[i] = strdup(trash);
                Time[i] = strdup(time);
                sscanf(mac_s, "%x:%x:%x:%x:%x:%x", &mac1[0], &mac1[1], &mac1[2], &mac1[3], &mac1[4], &mac1[5]);
                sscanf(mac_d, "%x:%x:%x:%x:%x:%x", &mac2[0], &mac2[1], &mac2[2], &mac2[3], &mac2[4], &mac2[5]);
                for(j = 0; j < 6; j++){
                        Mac1[i].address_bytes[j] = (uint8_t) mac1[j];
                        Mac2[i].address_bytes[j] = (uint8_t) mac2[j];
                }
                printf ("Mac1[%d] is %02x:%02x:%02x:%02x:%02x:%02x and Time is %s\n", i, Mac1[i].address_bytes[0], Mac1[i].address_bytes[1], Mac1[i].address_bytes[2], Mac1[i].address_bytes[3],
                                 Mac1[i].address_bytes[4],  Mac1[i].address_bytes[5], Time[i]);
                printf ("Mac2[%d] is %02x:%02x:%02x:%02x:%02x:%02x \n", i, Mac2[i].address_bytes[0], Mac2[i].address_bytes[1], Mac2[i].address_bytes[2], Mac2[i].address_bytes[3],
                                 Mac2[i].address_bytes[4],  Mac2[i].address_bytes[5]);
       }
       i++;
    }

    printf(" \n  time0 is %s time1 is %s \n", Time[0], Time[1]);


    fclose(fptr);

}

如你所见，我是一个sscanf文件，有4个变量，然后我把mac地址分别写成sscanf类型的指针，然后尝试把它们写到一个结构数组中。我必须实现uint8_t值。

此代码的输出为：

communication1 : b8:27:eb:cf:54:2c, b8:27:eb:75:85:e4, 2000000;
Mac1[0] is b8:27:eb:cf:54:2c and Time is 2000000
Mac2[0] is b8:27:eb:75:85:e4 

communication2 : mm:27:eb:cf:54:2c, xx:27:eb:75:85:e4, 2200000;
Mac1[1] is b8:27:eb:cf:54:2c and Time is 2200000
Mac2[1] is b8:27:eb:75:85:e4 

  time0 is 2000000 time1 is 2200000 

问题是，我找不到将指针复制到结构数组的uint8_t字段中的方法。对于字符串，我已经得到了提示- strdup，那么uint8_t呢

Answer 1

要像uint8_t一样复制普通字节，请使用memcpy

int main() {
    uint8_t s[6] = { 0x1, 0x2, 0x3,0x4,0x5,0x6 };
    uint8_t *t;

    t = malloc(6*sizeof(uint8_t));
    memcpy(t,s,6*sizeof(uint8_t));
    printf("%x %x %x %x %x %x\n", t[0],t[1],t[2],t[3],t[4],t[5]);
}