我有一个2D彩色图像和一个标签图像(标签的投影)
标签图像的输出如下:
[[16 16 16 ... 16 16 16 ]
[16 16 16 ... 16 16 16 ]
[16 16 16 ... 16 16 16 ]
...
[ 2 2 2 ... 2 2 2 ]
[ 2 2 2 ... 2 2 2 ]
[ 2 2 2 ... 2 2 2 ]]如何在原始2D彩色图像中的所有对象(由标签表示)周围绘制边界框?
发布于 2020-10-20 16:59:39
使用NumPy的boolean array indexing和OpenCV的boundingRect函数可以很容易地完成这项任务。
在here上,我拍摄了这张图片

这个分割掩码

蒙版是一个索引图像,OpenCV对此有问题,另请参阅here。这就是为什么,我们还将使用Pillow来完成此任务。
代码如下:
import cv2
import numpy as np
from PIL import Image
# Read color image
img = cv2.imread('0.jpg')
# Read mask; OpenCV can't handle indexed images, so we need Pillow here
# for that, see also: https://stackoverflow.com/q/59839709/11089932
mask = np.array(Image.open('0_mask.png'))
# Iterate all colors in mask
for color in np.unique(mask):
# Color 0 is assumed to be background or artifacts
if color == 0:
continue
# Determine bounding rectangle w.r.t. all pixels of the mask with
# the current color
x, y, w, h = cv2.boundingRect(np.uint8(mask == color))
# Draw bounding rectangle to color image
out = cv2.rectangle(img.copy(), (x, y), (x+w, y+h), (0, int(color), 0), 2)
# Show image with bounding box
cv2.imshow('img_' + str(color), out)
# Show mask
cv2.imshow('mask', mask)
cv2.waitKey(0)
cv2.destroyAllWindows()以下是输出:

我决定输出几个图像,因为对于给定的图像,边界框严重重叠。要将所有矩形绘制到同一图像,只需将相应的rectangle命令替换为
img = cv2.rectangle(img, (x, y), (x+w, y+h), (0, int(color), 0), 2)----------------------------------------
System information
----------------------------------------
Platform: Windows-10-10.0.16299-SP0
Python: 3.8.5
NumPy: 1.19.2
OpenCV: 4.4.0
Pillow: 7.2.0
----------------------------------------https://stackoverflow.com/questions/64437590
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