数组的JavaScript排序数组

Question

我想要根据数组，然后按数组中项的长度对数组进行排序。

采用以下主排序数组：

const key = [
  "meraki",
  "gsuite",
  "active directory",
  "sophos",
  "manageengine"
]

我想要一个类似如下的数组：

const raw = [
  ["manageengine"],
  ["sophos"],
  ["active directory"],
  ["gsuite"],
  ["meraki"],
  ["sophos", "manageengine"],
  ["active directory", "sophos"],
  ["active directory", "manageengine"],
  ["gsuite", "active directory"],
  ["gsuite", "sophos"],
  ["gsuite", "manageengine"],
  ["meraki", "gsuite"],
  ["meraki", "active directory"],
  ["meraki", "sophos"],
  ["meraki", "manageengine"],
  ["active directory", "sophos", "manageengine"],
  ["gsuite", "active directory", "sophos"],
  ["gsuite", "active directory", "manageengine"],
  ["gsuite", "sophos", "manageengine"],
  ["meraki", "gsuite", "active directory"],
  ["meraki", "gsuite", "sophos"],
  ["meraki", "active directory", "sophos"],
  ["meraki", "gsuite", "manageengine"],
  ["meraki", "active directory", "manageengine"],
  ["meraki", "sophos", "manageengine"],
  ["gsuite", "active directory", "sophos", "manageengine"],
  ["meraki", "gsuite", "active directory", "sophos"],
  ["meraki", "gsuite", "active directory", "manageengine"],
  ["meraki", "gsuite", "sophos", "manageengine"],
  ["meraki", "active directory", "sophos", "manageengine"],
  ["meraki", "gsuite", "active directory", "sophos", "manageengine"]
];

在上面的示例中，我希望根据key数组中的每一项对raw数组进行排序。我的第一次尝试是这样做的：

const result = [];
for (const name of result) {
  const sorted = keys.filter((s) => s[0] === name);
  result.push(...sorted);
}

result.sort((a, b) => a.length - b.length);

然而，这只考虑了数组中的第一项，而不考虑其余项的排序。

Answer 1

要排序，你必须首先检查长度。如果两者相等，我们必须检查a/b的第一个元素在key中的索引位置。如果它们是相同的，则移动到两个数组中的下一个元素。

这个答案利用了0是一个假值这一事实。例如：0 || -1 //=> -1和1 || -1 //=> 1

​

const key = ["meraki", "active directory", "sophos"];

const raw = [
  ["meraki"],
  ["active directory"],
  ["sophos", "active directory"],
  ["active directory", "sophos"],
  ["sophos"],
  ["meraki", "active directory", "sophos"],
];

raw.sort((a, b) => (
  a.length - b.length || a.reduce((diff, _, i) => (
    diff || key.indexOf(a[i]) - key.indexOf(b[i])
  ), 0)
));

console.log(raw);
console.table(raw); // check browser console

​

Answer 2

考虑下面的方法

​

const key = [
  "meraki",
  "active directory",
  "sophos"
]
const raw = [
   ["sophos"],
   ["meraki"],
   ["active directory"],
   ["sophos", "active directory"],
   ["active directory", "sophos"],
   ["meraki", "active directory", "sophos"]
]

const compareThis = (a, b) => {
  if (a.length !== b.length) {
    return a.length - b.length
  }
  let itemFound = 0;
  for (let keyIndex in key) {
    for (let aIndex in a ) {
      if(a[aIndex] === key[keyIndex]) {
        itemFound = -1;
        break;
      }
      if(b[aIndex] === key[keyIndex]) {
        itemFound = 1;
        break;
      }
    }
    if(itemFound !== 0) { break }
  }
  return itemFound;
}

const sortedData = raw.sort(compareThis)

console.log(sortedData)

​