为什么我的函数在我调用它的时候不能激活？

Question

import random
def main():
   num_guesses = 4


   instruction_file=open('instructions.txt', 'r')

   list_of_words = ['apple', 'banana', 'watermelon', 'kiwi', 'pineapple', 'mango']
   answer=random.choice(list_of_words)
   puzzle=['_'] * len(answer)




   def display_instructions(instruction_file):
      file_contents=instruction_file.read()
      instruction_file=instruction_file.close()
      print(file_contents)





   def get_guess(num_guesses):
      print('The number of guesses remaining is ' + str(num_guesses)+ '.') 
      letter_input = input("Guess a letter ")
      return letter_input

   def update_puzzle_string(letter_input,puzzle,answer):
      if get_guess(num_guesses) in answer:
         for i,x in enumerate(answer):
            if x is get_guess:
               puzzle[i]=letter_input
               return True


   def display_puzzle_string(puzzle):
      print('The current state of the puzzle is '+str(puzzle))

   def is_word_found(puzzle,answer):
      is_word_found=True
      puzzle_string=print(''.join(puzzle))
      if puzzle_string == answer:
         return False





   def play_game(answer,puzzle):
      while True:
         display_puzzle_string(puzzle)
         get_guess(num_guesses)
         update_puzzle_string(get_guess,puzzle,answer)
         print(str(puzzle))



   is_word_found(puzzle,answer)
   display_instructions(instruction_file)         
   play_game(answer,puzzle)







main()

很抱歉出现格式化问题。这个程序的目标是收集用户的猜测，然后将其与列表中随机选择的单词进行比较，这样做后，它会更新一个拼图，其中包含字母所属的空格，如果猜到了单词的所有字母，用户就会被告知它们是正确的。用户得到4次猜测。它基本上就是一个绞刑者。当我执行这个程序时，它只是打印指令，初始的拼图状态，请求猜测，然后一直要求猜测。我不明白为什么这不管用。在获得帮助后，我将实现猜测的次数。

Answer 1

import random
def main():
    num_guesses = 4
    instruction_file=open('instructions.txt', 'r')

    list_of_words = ['apple', 'banana', 'watermelon', 'kiwi', 'pineapple', 'mango']
    answer=random.choice(list_of_words)
    puzzle=['_'] * len(answer)

    def display_instructions(instruction_file):
        file_contents=instruction_file.read()
        instruction_file=instruction_file.close()
        print(file_contents)

    def get_guess(num_guesses):
        print('The number of guesses remaining is ' + str(num_guesses)+ '.') 
        letter_input = input("Guess a letter: ")
        return letter_input

    def update_puzzle_string(letter_input,puzzle,answer):
        for i,x in enumerate(answer):
            if x is letter_input:
                puzzle[i]=letter_input
        return

    def display_puzzle_string(puzzle):
        print('The current state of the puzzle is '+str(puzzle))

    def is_word_found(puzzle,answer):
        is_word_found=True
        puzzle_string=print(''.join(puzzle))
        if puzzle_string == answer:
            return False
                
    def play_game(answer,puzzle):
        while True:
            display_puzzle_string(puzzle) #display '_ _ _ _ _'
            guess = get_guess(num_guesses)
            update_puzzle_string(guess,puzzle,answer)
            #print(str(puzzle)) #this statement is causing the repetitive puzzle prints

    is_word_found(puzzle,answer)
    display_instructions(instruction_file)
    play_game(answer,puzzle)

main()

在修复了格式化问题之后，代码现在反复请求猜测并接受输入。我认为问题主要存在于格式上，因为我现在没有得到错误。另外，你之前有没有随机导入？干杯

编辑：

请参阅对update_puzzle_string()和play_game的更改。您反复调用get_guess函数，而不是使用它的初始返回值。

​

编辑2：(请参考此答案的注释)

有关“答案中相同字母的倍数”的更改，请参见update_puzzle_string()

​

Answer 2

所以你的错误是不能停止软件？

您可以在play_game中使用is_word_found，如果找到则中断。

如下所示：

def play_game(answer,puzzle):
    while True:
        display_puzzle_string(puzzle)
        get_guess(num_guesses)
        update_puzzle_string(get_guess,puzzle,answer)
        if is_word_found(puzzle, answer):
            print("You won!")
            break
        print(str(puzzle))

Break将停止while True无限循环