拆分列表中的值并创建2个新列表

Question

我有list = 'https://pagerduty.com/teams/PRJMI0O'，'https://pagerduty.com/services/PRWZID9'，'https://pagerduty.com/service-directory/PJNKJWD'.

我想提取/teams url和/service* url的单独列表。并将-1索引添加到新列表中。

示例：

INPUT list:
list = ['https://pagerduty.com/teams/PRJMI0O', 'https://pagerduty.com/services/PRWZID9', 'https://pagerduty.com/service-directory/PJNKJWD']

Expected OUTPUT
new_teams = ["PRJMI0O"]
new_service = ["PRWZID9", "PJNKJWD"]

please advice the logic.

Answer 1

提示:您可以使用split function。

>>> 'https://pagerduty.com/teams/PRJMI0O'.split('/')
['https:', '', 'pagerduty.com', 'teams', 'PRJMI0O']

答:让urls成为你所关心的列表。

new_teams = []
new_services = []
for url in urls:
    urlSplit = url.split('/')
    if 'teams' in urlSplit:
        new_teams.append(urlSplit[-1])
    if 'services' in urlSplit:
        new_services.append(urlSplit[-1])