我有一个代码,插入数据从一个模态表单到两个相关的表,即inventory_order表和inventory_order_product表。代码运行得很好,但是当我想要将相同的数据取回到模式表单中进行编辑时,我的问题就出现了。fetch single的代码只检索selectpicker中第一行的数据,而不检索其余行的数据。如果我的问题不清楚,请看下面的图片,请耐心等待我,我是php,ajax和mysql的新手。

$(document).on('click', '.update', function(){
var inventory_order_id = $(this).attr("id");
var btn_action = 'fetch_single';
$.ajax({
url:"order_action.php",
method:"POST",
data:{inventory_order_id:inventory_order_id, btn_action:btn_action},
dataType:"json",
success:function(data)
{
$('#orderModal').modal('show');
$('#inventory_order_name').val(data.inventory_order_name);
$('#inventory_order_date').val(data.inventory_order_date);
$('#inventory_order_address').val(data.inventory_order_address);
$('#span_product_details').html(data.product_details);
$('#payment_status').val(data.payment_status);
$('.modal-title').html("<i class='fa fa-pencil-square-o'></i> Edit Order");
$('#inventory_order_id').val(inventory_order_id);
$('#action').val('Edit');
$('#btn_action').val('Edit');
}
})
}); if($_POST['btn_action'] == 'fetch_single')
{
$query = "
SELECT * FROM inventory_order WHERE inventory_order_id = :inventory_order_id
";
$statement = $connect->prepare($query);
$statement->execute(
array(
':inventory_order_id' => $_POST["inventory_order_id"]
)
);
$result = $statement->fetchAll();
$output = array();
foreach($result as $row)
{
$output['inventory_order_name'] = $row['inventory_order_name'];
$output['inventory_order_date'] = $row['inventory_order_date'];
$output['inventory_order_address'] = $row['inventory_order_address'];
$output['payment_status'] = $row['payment_status'];
}
$sub_query = "
SELECT * FROM inventory_order_product
WHERE inventory_order_id = '".$_POST["inventory_order_id"]."'
";
$statement = $connect->prepare($sub_query);
$statement->execute();
$sub_result = $statement->fetchAll();
$product_details = '';
$count = '';
$count = $count++;
foreach($sub_result as $sub_row)
{
$product_details .= '
<script>
$(document).ready(function(){
$("#product_id'.$count.'").selectpicker("val", '.$sub_row["product_id"].');
$(".selectpicker").selectpicker();
});
</script>
<span id="row'.$count.'">
<div class="row">
<div class="col-md-8">
<select name="product_id[]" id="product_id'.$count.'" class="form-control selectpicker" data-live-search="true" required>
'.fill_product_list($connect).'
</select>
<input type="hidden" name="hidden_product_id[]" value="'.$sub_row["product_id"].'" />
</div>
<div class="col-md-3">
<input type="text" name="quantity[]" class="form-control" value="'.$sub_row["quantity"].'" required />
</div>
<div class="col-md-1">
';
if($count == '')
{
$product_details .= '<button type="button" name="add_more" id="add_more" class="btn btn-success btn-xs">+</button>';
}
else
{
$product_details .= '<button type="button" name="remove" id="'.$count.'" class="btn btn-danger btn-xs remove">-</button>';
}
$product_details .= '
</div>
</div>
</div><br />
</span>
';
}
$output['product_details'] = $product_details;
echo json_encode($output);
}
发布于 2020-07-20 22:00:36
你的代码的问题是后端代码中的变量选择器,这是在你的foreach..循环之外声明的,所以当你的循环第一次运行时,它会有正确的值,即:0,但你永远不会递增它,这就是为什么它只给第一个选择器提供正确的值。相反,您需要增加它的值来设置第二个值、第三个值等等。即:
foreach($sub_result as $sub_row)
{
//you code html and jquery
$count = $count++;//add this inside for loop
}还有,我不明白你为什么要给$count = '';。相反,它应该是$count = 0;
https://stackoverflow.com/questions/62991083
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