如何防止在视图解除动画功能结束之前接触视图？

Question

我有一个自定义的java类，它扩展了位于扩展FrameLayout的另一个自定义父视图之上的FrameLayout

我有下面的函数，它用动画消除视图-

private void dismissCard(final View view, int xPos) {
    view.animate()
        .x(xPos)
        .y(0)
        .setInterpolator(new AccelerateInterpolator())
        .setDuration(DURATION)
        .setListener(new Animator.AnimatorListener() {
          @Override
          public void onAnimationStart(Animator animator) {
            setOnTouchListener(null);
          }
          @Override
          public void onAnimationEnd(Animator animator) {
            ViewGroup viewGroup = (ViewGroup) view.getParent();
            if (viewGroup != null) {
              viewGroup.removeView(view);
            }
          }
          @Override
          public void onAnimationCancel(Animator animator) {
          }
          @Override
          public void onAnimationRepeat(Animator animator) {
          }
        });
  }

问题是，我重写了用于移动视图功能的onTouch()函数，对于每一次触摸，我都会获得视图的父级，这是一个自定义视图，获得视图的所有子级，并通过确定哪个视图在顶部。所以我的问题是，虽然是动画，但动画视图仍然在顶部，所以它可以移动到另一个时间，直到动画消失，viewGroup.removeView(view)被调用。

下面是我的onTouch()实现：

@Override
  public boolean onTouch(final View view, MotionEvent motionEvent) {
    TinderStackLayout tinderStackLayout = ((TinderStackLayout) view.getParent());
    TinderCardView topCard = (TinderCardView) tinderStackLayout.getChildAt(tinderStackLayout.getChildCount() - 1);
    if (topCard.equals(view)) {
      switch (motionEvent.getAction()) {
        case MotionEvent.ACTION_DOWN:
          oldX = motionEvent.getX();
          oldY = motionEvent.getY();
          // cancel any current animations
          view.clearAnimation();
          return true;
        case MotionEvent.ACTION_UP:
          if (isCardBeyondLeftBoundary(view)) {
            Log.d("top card dismissed - ", topCard.usernameTextView.getText().toString());
            onCardSwipedListener.send(new TopCardMovedEvent(-(screenWidth)));
            dismissCard(view, -(screenWidth * 2));
          } else if (isCardBeyondRightBoundary(view)) {
            showLawyerContactDetailsFragment(topCard);
            onCardSwipedListener.send(new TopCardMovedEvent(-(screenWidth)));
            resetCard(view);
          } else {
            onCardSwipedListener.send(new TopCardMovedEvent(-(screenWidth)));
            resetCard(view);
          }
          return true;
        case MotionEvent.ACTION_MOVE:
          newX = motionEvent.getX();
          newY = motionEvent.getY();
          dX = newX - oldX;
          dY = newY - oldY;
          float posX = view.getX() + dX;
          onCardSwipedListener.send(new TopCardMovedEvent(-(screenWidth)));
          // Set new position
          view.setX(view.getX() + dX);
          view.setY(view.getY() + dY);
          setCardRotation(view, view.getX());
          updateAlphaOfBadges(posX);
          return true;
        default:
          return super.onTouchEvent(motionEvent);
      }
    }
    return super.onTouchEvent(motionEvent);
  }

我缺少的是一种在dismissCard()动画时阻止触摸能力的方法。我该如何实现这样的东西呢？

Answer 1

在要设置动画的类中声明一个布尔变量(IsAnimating)，并在onAnimationStart中将其设置为true，在onAnimationEnd中将其设置为false。

在onTouch中访问此变量

@Override
  public boolean onTouch(final View view, MotionEvent motionEvent) {
    TinderStackLayout tinderStackLayout = ((TinderStackLayout) view.getParent());
    TinderCardView topCard = (TinderCardView) tinderStackLayout.getChildAt(tinderStackLayout.getChildCount() - 1);
    if (topCard.equals(view)&& !isAnimating) { //access event's only if animation is ended.
      switch (motionEvent.getAction()) {
        case MotionEvent.ACTION_DOWN:
          oldX = motionEvent.getX();
          oldY = motionEvent.getY();
          // cancel any current animations
          view.clearAnimation();
          return true;
        case MotionEvent.ACTION_UP:
          if (isCardBeyondLeftBoundary(view)) {
            Log.d("top card dismissed - ", topCard.usernameTextView.getText().toString());
            onCardSwipedListener.send(new TopCardMovedEvent(-(screenWidth)));
            dismissCard(view, -(screenWidth * 2));
          } else if (isCardBeyondRightBoundary(view)) {
            showLawyerContactDetailsFragment(topCard);
            onCardSwipedListener.send(new TopCardMovedEvent(-(screenWidth)));
            resetCard(view);
          } else {
            onCardSwipedListener.send(new TopCardMovedEvent(-(screenWidth)));
            resetCard(view);
          }
          return true;
        case MotionEvent.ACTION_MOVE:
          newX = motionEvent.getX();
          newY = motionEvent.getY();
          dX = newX - oldX;
          dY = newY - oldY;
          float posX = view.getX() + dX;
          onCardSwipedListener.send(new TopCardMovedEvent(-(screenWidth)));
          // Set new position
          view.setX(view.getX() + dX);
          view.setY(view.getY() + dY);
          setCardRotation(view, view.getX());
          updateAlphaOfBadges(posX);
          return true;
        default:
          return super.onTouchEvent(motionEvent);
      }
    }
    return super.onTouchEvent(motionEvent);
  }

附注-更好的解决方案是当isAnimating为true.In我的应用程序重写了父类中的分派接触时返回false，并且不让任何事件到达父类或它的任何子类。

override fun dispatchTouchEvent(ev: MotionEvent?): Boolean {
 if (isAnimationOnGoing) {
        return false
 }
 return super.dispatchTouchEvent(ev)
}