Javascript -根据其他json的值过滤geojson

Question

我正在努力根据另一个JSON的值过滤一个geojson。具体地说，我正在尝试根据另一个json中的id过滤geojson。每次，我过滤后的geojson都会返回null。

我已经创建了一个JSfiddle here来显示我想要做的事情。

代码是

    mygeojson={crs: {properties: {name: "EPSG:4326"}, type: "name"},
features: [
    {geometry: {coordinates: [25, 37], type: "Point"},properties: {"wineryid":3},type:"Feature"},
  {geometry: {coordinates: [26, 37], type: "Point"},properties: {"wineryid":45},type:"Feature"},
  {geometry: {coordinates: [25, 38], type: "Point"},properties: {"wineryid":34},type:"Feature"},
  {geometry: {coordinates: [28, 37], type: "Point"},properties: {"wineryid":42},type:"Feature"},
  {geometry: {coordinates: [25, 342], type: "Point"},properties: {"wineryid":80},type:"Feature"},
  {geometry: {coordinates: [25.24, 37.12], type: "Point"},properties: {"wineryid":120},type:"Feature"}], type:"FeatureCollection"};
mylist=[{id:1, name:"test1"},{id:34,name:"test2"}];
tempgeojson = mygeojson.features.filter(function (item) {
  return (mylist.every(f => item.properties.id === f.id) )
});
filteredgeojson={};
filteredgeojson.features=tempgeojson;
filteredgeojson.crs=mygeojson.crs;
filteredgeojson.type="FeatureCollection";

我怎样才能得到我需要的过滤过的geojson？(在本例中，预期的geojson大约是id的1和34。)

Answer 1

尝试使用以下代码进行要素过滤

filteredgeojson.features = mygeojson.features.filter(item => { 
     if(mylist.filter(myitem => myitem.id === item.properties.wineryid).length > 0) { 
          return item;
      }
});