使用path-to-regexp匹配尽可能多的URL路由参数？

Question

我想要一种方法来匹配尽可能多的URL参数的例子

/teams/:teamID/players/:playerID/seasons/:seasonID/detail

将匹配任何以/teams开头的内容，并匹配所有存在的参数，最多为/detail (最多为)

/Giants => { teamID: null, playerID: null, seasonID: null }
/Giants/123 => { teamID: 123, playerID: null, seasonID: null }
/Giants/123/players/ => same as above
/Giants/123/players/456/seasons/2020/detail => { teamId: 123, playerID: 456, seasonID: 2020 }
/Giants/123/players/446/seasons/2020 => same as above

和不匹配

/Giants/123/players/456/seasons/2020/detail/12345

我使用的是path-to-regexp。

Answer 1

我发现了一个很好的库，它完全满足了我的需求，非常轻便，并且使用经过良好测试的Backbone.js片段来进行模式匹配：

https://github.com/HenrikJoreteg/feather-route-matcher

示例：

pattern: '/users/:id' 
url: '/something-else' 
extracted params: nothing, because it won't match

pattern: '/users/:id' 
url: '/users/scrooge-mc-duck' 
extracted params: {id: 'scrooge-mc-duck'}

pattern: '/users/:id' 
url: '/users/47' 
extracted params: {id: '47'}

pattern: '/schools/:schoolId/teachers/:teacherId' 
url: '/schools/richland/teachers/47' 
extracted params: {schoolId: 'richland', teacherId: '47'}

这提供了我想要和需要的东西

Answer 2

如果有可能不使用正则表达式，您可能可以使用/作为分隔符将URL拆分为一个数组。获取数组中在team之后一直到details的每个元素。