有没有办法对浮点数使用_pickBy()来过滤对象

Question

我正在尝试过滤一个对象，并使用_pickBy lodash方法过滤到只显示9.8以上的版本。但它并没有像预期的那样工作。我的代码如下：

let test_obj= {
 "version-1":{
      "path":"abcd",
      "version":"9.1"
   },
   "version-2":{
      "path":"efgh",
      "version":"9.9.1"
   },
   "version-3":{
      "path":"bbbbbb",
      "version":"9.10.0"
   },
   "version-4":{
      "path":"cccccc",
      "version":"9.9.0"
   },
   "version-5":{
      "path":"kkkkkkk",
      "version":"9.8"
   }
}

let output = _.pickBy(test_obj, (v,k) => v.version === "" || parseFloat(v.version) >= parseFloat(9.8));

上面代码的输出是，

{
       "version-2":{
          "path":"efgh",
          "version":"9.9.1"
       },
       "version-4":{
          "path":"cccccc",
          "version":"9.9.0"
       },
       "version-5":{
          "path":"kkkkkkk",
          "version":"9.8"
       }
    }

JS小提琴：https://jsfiddle.net/ufzh7631/

它也应该添加"version-3"，因为它大于9.8。但它省略了9.10.0。有没有办法做到这一点。任何帮助都将不胜感激。

Answer 1

您可以在options参数中使用带有numeric: true的localeCompare

v.version.localeCompare("9.8", undefined, { 'numeric': true }) >= 0

即使在像9.8.1这样的版本中有超过1个小数点时，这也是有效的

​

let test_obj = {
  "version-1": {
    "path": "abcd",
    "version": "9.1"
  },
  "version-2": {
    "path": "efgh",
    "version": "9.9.1"
  },
  "version-3": {
    "path": "bbbbbb",
    "version": "9.10.0"
  },
  "version-4": {
    "path": "cccccc",
    "version": "9.9.0"
  },
  "version-5": {
    "path": "kkkkkkk",
    "version": "9.8"
  }
}

let output = _.pickBy(
  test_obj,
  v => v.version === "" || v.version.localeCompare("9.8", undefined, { 'numeric': true }) >= 0);

console.log(output)

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.20/lodash.min.js" integrity="sha512-90vH1Z83AJY9DmlWa8WkjkV79yfS2n2Oxhsi2dZbIv0nC4E6m5AbH8Nh156kkM7JePmqD6tcZsfad1ueoaovww==" crossorigin="anonymous"></script>

​