我正在尝试创建一个基本的crud服务,该服务采用Sequelize模型并为其创建所有基本API,因此我所做的是:
export class RepositoryService<T extends Model<T>> {
constructor(protected model: typeof Model) {
}
public async getMany(
query: RequestParamsParsed = {},
options: RestfulOptions = {},
): Promise<T[]> {
return this.model.findAll();
}
}我得到以下错误:
The 'this' context of type 'typeof Model' is not assignable to method's 'this' of type 'new () => Model<Model<any>>'.
Cannot assign an abstract constructor type to a non-abstract constructor type.这是因为seqeulize-typescript包中的这一行:
static findAll<T extends Model<T>>(this: (new () => T), options?: IFindOptions<T>): Promise<T[]>;我对Typescript比较陌生,所以如果有人能告诉我findAll函数中的this: (new () => T)是什么意思,我该如何解决这个问题。
发布于 2019-03-18 04:22:20
问题似乎出在这条线上。
constructor(protected model: typeof Model) {}我设置模型类型的Model是从sequelize-typescript导入的,而我应该使用从sequelize本身导出的原始模型。
整个代码是这样的:
import { Model as OriginalModel } from 'sequelize';
import { Model } from 'sequelize-typescript';
export class RepositoryService<T extends Model<T>> {
constructor(protected model: typeof OriginalModel) {
}
public async getMany(
query: RequestParamsParsed = {},
options: RestfulOptions = {},
): Promise<T[]> {
return this.model.findAll();
}
}发布于 2020-01-06 17:44:36
在使用sequelize-typescript库时也遇到了此错误。
您可以首先定义这些帮助器类型:
import { Model } from "sequelize-typescript";
// Type `ModelType` would basically wrap & satisfy the 'this' context of any sequelize helper methods
type Constructor<T> = new (...args: any[]) => T;
type ModelType<T extends Model<T>> = Constructor<T> & typeof Model;然后,在您的代码中使用它:
export class RepositoryService<T extends Model<T>> {
constructor(protected model: ModelType<T>) {}
public async getMany(
query: RequestParamsParsed = {},
options: RestfulOptions = {},
): Promise<T[]> {
return this.model.findAll();
}
}希望这能有所帮助。
发布于 2021-06-26 11:06:51
使用"sequelize-typescript": "2.1.0",你可以使用模块提供的ModelCtor,例如。
import { Model, ModelCtor } from 'sequelize-typescript';
export class RepositoryService<T extends Model<T>> {
constructor(protected model: ModelCtor<T>) {}
public async getMany(
query: RequestParamsParsed = {},
options: RestfulOptions = {}
): Promise<T[]> {
return this.model.findAll();
}
}ModelCtor类型为:
export declare type Repository<M> = (new () => M) & NonAbstract<typeof Model>;
export declare type ModelCtor<M extends Model = Model> = Repository<M>;https://stackoverflow.com/questions/55166230
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