去掉字符串输出中的制表符、换行符和空格，但保留一个空格，这样单词就不会连接在一起

Question

我有一个list_3，只有一个元素，一个字符串：

[['\n\n\n Headquarters or Regional Office\n\n\n\n\n\t\t\t\t\t\t\t\t\tMain Headquarters\t\t\t\t\t\t\t\n\n', '\n\n\n Founders\n\n\n\n\n\t\t\t\t\t\t\t\t\tThomas Lon Van\t\t\t\t\t\t\t\n\n', '\n\n\n Founder Diversity\n\n\n\n\n\t\t\t\t\t\t\t\t\tN/A\t\t\t\t\t\t\t\n\n', '\n\n\n Year Founded\n\n\n\n\n\t\t\t\t\t\t\t\t\t2016\t\t\t\t\t\t\t\n\n', '\n\n\n # of Employees\n\n\n\n\n\t\t\t\t\t\t\t\t\t1-10\t\t\t\t\t\t\t\n\n', '\n\n\n Seeking Funding?\n\n\n\n\n\t\t\t\t\t\t\t\t\tNo \t\t\t\t\t\t\t\n\n', '\n\n\n Funding Phase\n\n\n\n\n\t\t\t\t\t\t\t\t\tN/A\t\t\t\t\t\t\t\n\n'], ['\n\n\n Headquarters or Regional Office\n\n\n\n\n\t\t\t\t\t\t\t\t\tMain Headquarters\t\t\t\t\t\t\t\n\n', '\n\n\n Founders\n\n\n\n\n\t\t\t\t\t\t\t\t\tMacKenzie T Stout,\t\t\t\t\t\t\t\n\n', '\n\n\n Founder Diversity\n\n\n\n\n\t\t\t\t\t\t\t\t\tN/A\t\t\t\t\t\t\t\n\n', '\n\n\n Year Founded\n\n\n\n\n\t\t\t\t\t\t\t\t\t2020\t\t\t\t\t\t\t\n\n', '\n\n\n # of Employees\n\n\n\n\n\t\t\t\t\t\t\t\t\t1-10\t\t\t\t\t\t\t\n\n', '\n\n\n Seeking Funding?\n\n\n\n\n\t\t\t\t\t\t\t\t\tYes\t\t\t\t\t\t\t\n\n', '\n\n\n Funding Phase\n\n\n\n\n\t\t\t\t\t\t\t\t\tPre-Seed\t\t\t\t\t\t\t\n\n']]

我想使用正则表达式从输出中剥离\n\t\r，并以易于阅读的格式返回文本

这是我尝试过的：

list_33 = []
for i in list_3:
     string = ''.join(list_3)
     list_33.append(re.sub('\s+','', string))
print(list_33)

输出：

['HeadquartersorRegionalOfficeMainHeadquarters', 'FoundersThomasLonVan', 'FounderDiversityN/A', 'YearFounded2016', '#ofEmployees1-10', 'SeekingFunding?No', 'FundingPhaseN/A']

这几乎就是我需要的，但我希望在list_3的第一个文本块之后，每个单词和冒号之间有一个空格，即：

['Headquarters or Regional Office: Main Headquarters', 'Founders: Thomas Lon Van', 'Founder Diversity: N/A', 'Year Founded: 2015', '# of Employees 1-10', 'Seeking Funding?: No', 'Funding Phase: N/A']

关于如何将两个regex函数合并为一个函数，您有什么想法吗？

谢谢

ps。我知道我不需要为只有一个元素的列表使用for循环，但在未来列表将有更多的元素，我现在正在尝试使用一个输入来泛化代码结构。

Answer 1

您可以浏览列表中的每个字符串，并使用:替换每个出现2个以上空格的字符串

>>> import re
>>> lst = ['\n\n\n Headquarters or Regional Office\n\n\n\n\n\t\t\t\t\t\t\t\t\tMain Headquarters\t\t\t\t\t\t\t\n\n', '\n\n\n Founders\n\n\n\n\n\t\t\t\t\t\t\t\t\tThomas Lon Van\t\t\t\t\t\t\t\n\n', '\n\n\n Founder Diversity\n\n\n\n\n\t\t\t\t\t\t\t\t\tN/A\t\t\t\t\t\t\t\n\n', '\n\n\n Year Founded\n\n\n\n\n\t\t\t\t\t\t\t\t\t2016\t\t\t\t\t\t\t\n\n', '\n\n\n # of Employees\n\n\n\n\n\t\t\t\t\t\t\t\t\t1-10\t\t\t\t\t\t\t\n\n', '\n\n\n Seeking Funding?\n\n\n\n\n\t\t\t\t\t\t\t\t\tNo \t\t\t\t\t\t\t\n\n', '\n\n\n Funding Phase\n\n\n\n\n\t\t\t\t\t\t\t\t\tN/A\t\t\t\t\t\t\t\n\n']
>>> [re.sub(r'\s\s+', ': ', word).strip(': ') for word in lst]
['Headquarters or Regional Office: Main Headquarters', 'Founders: Thomas Lon Van', 'Founder Diversity: N/A', 'Year Founded: 2016', '# of Employees: 1-10', 'Seeking Funding?: No', 'Funding Phase: N/A']