我有一个类似如下的github操作:
const http = require('http');
const core = require('@actions/core');
const options = {
hostname: 'mydomain.com',
port: 80,
path: '/webhook',
method: 'POST',
headers: {
'Content-Type': 'application/x-www-form-urlencoded',
}
};
const postData = {
foo: 'bar'
}
try {
const strPostData = querystring.stringify(postData);
options.headers['Content-Length'] = Buffer.byteLength(strPostData);
const req = http.request(options)
req.write(strPostData)
req.end()
} catch (error) {
core.info(error.message);
}如果mydomain.com/webhook处于脱机状态,我的作业将在此操作中失败,并记录:
events.js:187
throw er; // Unhandled 'error' event
^
Error: connect ECONNREFUSED xxx.xxx.xxx.xxx:80
at TCPConnectWrap.afterConnect [as oncomplete] (net.js:1129:14)
Emitted 'error' event on ClientRequest instance at:
at Socket.socketErrorListener (_http_client.js:406:9)
at Socket.emit (events.js:210:5)
at emitErrorNT (internal/streams/destroy.js:92:8)
at emitErrorAndCloseNT (internal/streams/destroy.js:60:3)
at processTicksAndRejections (internal/process/task_queues.js:80:21) ***
errno: 'ECONNREFUSED',
code: 'ECONNREFUSED',
syscall: 'connect',
address: 'xxx.xxx.xxx.xxx',
port: 80
***为什么它失败了,为什么try catch没有捕捉到这一点?
如果此操作失败,我不希望整个作业失败,那么如何捕获此失败并对GitHub运行器隐藏它呢?
发布于 2021-01-27 15:12:12
您将需要侦听'error'事件来捕获此事件
const strPostData = querystring.stringify(postData);
options.headers['Content-Length'] = Buffer.byteLength(strPostData);
const req = http.request(options)
req.on('error', (err) => {/*Error Caught*/})
req.write(strPostData)
req.end()https://stackoverflow.com/questions/65914172
复制相似问题