如何在未应用过滤器的情况下使用django-filters保持页面分页？

Question

我正在使用django-filters来过滤类别和价格。我的问题是，当我过滤结果时，它是分页的，但当没有应用过滤器时，就没有分页。在没有应用过滤器的情况下，如何添加分页？提前感谢！

我的filters.py：

import django_filters
from .models import Item

class ItemFilter(django_filters.FilterSet):

    class Meta:
        model = Item

        fields = {
            'category': ['exact'],
            'price': ['lte']
        }

我的views.py：

class homeview(ListView):
    model = Item
    template_name = 'products/home.html'
    paginate_by = 8

    def get_context_data(self, **kwargs):
        context = super().get_context_data(**kwargs)
        context['filter'] = ItemFilter(self.request.GET, queryset=self.get_queryset())
        return context

我的home.html：

<div class="card">
          <div class="card-body">
            <div class="container">
              <form method="GET">
                {{ filter.form|crispy }}
                <button type="submit" class="btn btn-primary mt-4">Filter</button>
              </form>
            </div>
          </div>
        </div>

        <h1 class="mb-4">List Of Items</h1>
        <div class="row">
          {% for item in filter.qs %}
           ....
          {% endfor %}

Answer 1

class ListModelMixin:
    """
    List a queryset.
    """
    def list(self, request, *args, **kwargs):
        queryset = self.filter_queryset(self.get_queryset())

        page = self.paginate_queryset(queryset)
        if page is not None:
            serializer = self.get_serializer(page, many=True)
            return self.get_paginated_response(serializer.data)

        serializer = self.get_serializer(queryset, many=True)
        return Response(serializer.data)```