JOOQ在调用select()时创建高逗号

Question

完成本教程后，我想创建一个小的select Query。

但在调用fetch()时，返回了以下错误：

org.jooq.exception.DataAccessException: SQL [select `LECTURE_DB`.`dbo`.`STUDENT`.`ID`, `LECTURE_DB`.`dbo`.`STUDENT`.`FIRSTNAME`, `LECTURE_DB`.`dbo`.`STUDENT`.`LASTNAME`, `LECTURE_DB`.`dbo`.`STUDENT`.`YEAR_OF_BIRTH`, `LECTURE_DB`.`dbo`.`STUDENT`.`GENDER` from `LECTURE_DB`.`dbo`.`STUDENT` -- SQL rendered with a free trial version of jOOQ 3.12.1]; Falsche Syntax in der Nähe von '`'.
at org.jooq_3.12.1.MYSQL.debug(Unknown Source)
at org.jooq.impl.Tools.translate(Tools.java:2717)
at org.jooq.impl.DefaultExecuteContext.sqlException(DefaultExecuteContext.java:755)
at org.jooq.impl.AbstractQuery.execute(AbstractQuery.java:383)
at org.jooq.impl.AbstractResultQuery.fetch(AbstractResultQuery.java:353)
at org.jooq.impl.SelectImpl.fetch(SelectImpl.java:2693)
at de.esteam.lecturedb.jooq.Classes.Startup.main(Startup.java:32)
Caused by: com.microsoft.sqlserver.jdbc.SQLServerException: Falsche Syntax in der Nähe von '`'.

将query复制到SQL Server时，查询也不正确。

我该如何解决这个问题呢？查询本身是正确的(正确的列)。

代码是由codegen自动生成的。

主要方法：

public static void main(String[] args)
{
    // TODO Auto-generated method stub
    String userName = "SampleUser";
    String password = "SamplePwd";
    String url = "jdbc:sqlserver://SampleURL;databaseName=LECTURE_DB";

    // Connection is the only JDBC resource that we need
    // PreparedStatement and ResultSet are handled by jOOQ, internally
    try  {
        Connection conn = DriverManager.getConnection(url, userName, password);
        DSLContext create = DSL.using(conn, SQLDialect.MYSQL);
        Result<Record> result = create.select().from(Student.STUDENT).fetch();

        for (Record r : result) {
            Integer id = r.getValue(Student.STUDENT.ID);
            String firstName = r.getValue(Student.STUDENT.FIRSTNAME);
            String lastName = r.getValue(Student.STUDENT.LASTNAME);

            System.out.println("ID: " + id + " first name: " + firstName + " last name: " + lastName);
        }
    } 

    // For the sake of this tutorial, let's keep exception handling simple
    catch (Exception e) {
        e.printStackTrace();
    }

}

Answer 1

愚蠢的我。

正如@AlwaysLearning提到的，我用错了方言！

它应该是SQLDialect.SQLSERVER2014，而不是SQLDialect.MYSQL