React路由器V6路由

Question

我正在尝试用新发布的路由器实现一个PrivateRoute逻辑，但它似乎没有像预期的那样工作。

import { Route, Routes, Navigate } from "react-router-dom";

import LogInPage from "./pages/LogIn";
import DashboardPage from "./pages/Dashboard";

function PrivateRoute({ path, element }) {
  const auth = true;

  return (
    <Route
      path={path}
      element={auth === true ? element : <Navigate replace to="/login" />}
    />
  );
}

function App() {
  return (
    <Routes>
      <Route path="/*" element={<PageNotFound />} />
      <Route path="/" element={<Navigate replace to="/dashboard" />} />
      <Route path="/login" element={<LogInPage />} />
      <PrivateRoute
        path="/dashboard"
        element={<DashboardPage />}
      />
    </Routes>
  );
}

export default App;

我遗漏了什么？如果PrivateRoute组件返回一个Route，那么它不是仍然是一个Route组件吗？

Answer 1

React路由器v6中的You cannot compose Route%s。相反，应在与其他路由相同的级别创建路由，并在element属性中使用PrivateRoute组件。示例(source)：

import { Routes, Route, Navigate } from "react-router-dom";

function App() {
  return (
    <Routes>
      <Route path="/public" element={<PublicPage />} />
      <Route
        path="/protected"
        element={
          // Good! Do your composition here instead of wrapping <Route>.
          // This is really just inverting the wrapping, but it's a lot
          // more clear which components expect which props.
          <RequireAuth redirectTo="/login">
            <ProtectedPage />
          </RequireAuth>
        }
      />
    </Routes>
  );
}

function RequireAuth({ children, redirectTo }) {
  let isAuthenticated = getAuth();
  return isAuthenticated ? children : <Navigate to={redirectTo} />;
}