blocks|key|921318|text|列：awk+'{print+NF}'+file+%7C+sort+-nu+%7C+tail+-n+1|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|921319|使用head+-n+1表示最低列数，使用tail+-n+1表示最高列数。|921320|行：UUOC人群的cat+file+%7C+wc+-l或wc+-l+<+file。|921321|entityMap|0|LINK|mutability|MUTABLE|url|http://en.wikipedia.org/wiki/Cat_%2528Unix%2529#Useless_use_of_cat^0|2|18|0|2|9|K|9|0|9|G|Q|C|2|4|0|0^^$0|@$1|2|3|4|5|6|7|R|8|@$9|S|A|T|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|U|8|@$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|Z|8|@$9|10|A|11|B|C]|$9|12|A|13|B|C]]|D|@$9|14|A|15|1|16]]|E|$]]|$1|J|3|-4|5|6|7|17|8|@]|D|@]|E|$]]]|K|$L|$5|M|N|O|E|$P|Q]]]]

Columns: <code>awk '{print NF}' file | sort -nu | tail -n 1</code>

Use <code>head -n 1</code> for lowest column count, <code>tail -n 1</code> for highest column count.

Rows: <code>cat file | wc -l</code> or <code>wc -l &lt; file</code> for the <a href="http://en.wikipedia.org/wiki/Cat_%28Unix%29#Useless_use_of_cat">UUOC</a> crowd.

blocks|key|705074|text|或者，要对列进行计数，请对列之间的分隔符进行计数。我发现这很好地平衡了简洁性和易记性。当然，如果您的数据包含列分隔符，这将不起作用。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|705075|head+-n1+myfile.txt+%7C+grep+-o+"+"+%7C+wc+-l|code-block|syntax|javascript|705076|使用head+-n1抓取文件的第一行。使用grep+-o对所有空格进行计数，并输出在新行上找到的每个空格。使用wc+-l计算行数。|offset|length|style|CODE|705077|编辑:正如Gaurav+Tuli在下面指出的那样，我忘了提到你必须在脑海中将结果加1，否则就会编写这个数学脚本。|705078|entityMap^0|0|0|2|8|L|7|1J|5|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@$I|T|J|U|K|L]|$I|V|J|W|K|L]|$I|X|J|Y|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|Z|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|10|8|@]|9|@]|A|$]]]|P|$]]

Alternatively to count columns, count the separators between columns. I find this to be a good balance of brevity and ease to remember. Of course, this won't work if your data include the column separator.
<pre><code>head -n1 myfile.txt | grep -o &quot; &quot; | wc -l
</code></pre>
Uses <code>head -n1</code> to grab the first line of the file.
Uses <code>grep -o</code> to to count all the spaces, and output each space found on a new line. Uses <code>wc -l</code> to count the number of lines.
EDIT: As Gaurav Tuli points out below, I forgot to mention you have to mentally add 1 to the result, or otherwise script this math.

blocks|key|705013|text|如果您的文件很大，但您确定每行的列数保持不变(并且没有标题)，请使用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|705014|head+-n+1+FILE+%7C+awk+'{print+NF}'|code-block|syntax|javascript|705015|来查找列数，其中FILE是您的文件名。|705016|要找到行数，'wc+-l+FILE‘就可以了。|705017|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

If your file is big but you are certain that the number of columns remains the same for each row (and you have no heading) use:

<pre><code>head -n 1 FILE | awk '{print NF}'
</code></pre>

to find the number of columns, where FILE is your file name.

To find the number of lines 'wc -l FILE' will work.

blocks|key|921836|text|对kirill_igum的回答稍作改动，您就可以轻松地计算出所需的任何特定行的列数，这就是我提出这个问题的原因，尽管这个问题是针对整个文件的。(当然，如果您的文件的每一行都有相同的列，这也是可行的)：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|921837|head+-2+file+%7Ctail+-1+%7Ctr+'\t'+'\n'+%7Cwc+-l|code-block|syntax|javascript|921838|给出第2行的列数。例如，将2替换为55可获取第55行的列数。|921839|-bash-4.2$+cat+file
1+++++++2+++++++3
1+++++++2+++++++3+++++++4
1+++++++2
1+++++++2+++++++3+++++++4+++++++5

-bash-4.2$+head+-1+file+%7Ctail+-1+%7Ctr+'\t'+'\n'+%7Cwc+-l
3
-bash-4.2$+head+-4+file+%7Ctail+-1+%7Ctr+'\t'+'\n'+%7Cwc+-l
5|921840|如果您的文件由制表符分隔，则上面的代码可以工作，因为我们将其定义为"tr“。如果您的文件有另一个分隔符，例如逗号，您仍然可以使用相同的技巧计算“列"，只需将分隔符"t”更改为“，"：|921841|-bash-4.2$+cat+csvfile
1,2,3,4
1,2
1,2,3,4,5
-bash-4.2$+head+-2+csvfile+%7Ctail+-1+%7Ctr+'\,'+'\n'+%7Cwc+-l
2|921842|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

Little twist to kirill_igum's answer, and you can easily count the number of columns of any certain row you want, which was why I've come to this question, even though the question is asking for the whole file. (Though if your file has same columns in each line this also still works of course):

<pre><code>head -2 file |tail -1 |tr '\t' '\n' |wc -l
</code></pre>

Gives the number of columns of row 2.
Replace 2 with 55 for example to get it for row 55.

<pre><code>-bash-4.2$ cat file
1 2 3
1 2 3 4
1 2
1 2 3 4 5

-bash-4.2$ head -1 file |tail -1 |tr '\t' '\n' |wc -l
3
-bash-4.2$ head -4 file |tail -1 |tr '\t' '\n' |wc -l
5
</code></pre>

Code above works if your file is separated by tabs, as we define it to "tr". If your file has another separator, say commas, you can still count your "columns" using the same trick by simply changing the separator character "t" to ",":

<pre><code>-bash-4.2$ cat csvfile
1,2,3,4
1,2
1,2,3,4,5
-bash-4.2$ head -2 csvfile |tail -1 |tr '\,' '\n' |wc -l
2
</code></pre>

blocks|key|704971|text|您可以使用bash。注意对于以GB为单位的非常大的文件，请使用awk/wc。但是，对于几MB的文件，它在性能上应该仍然是可管理的。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|704972|declare+-i+count=0
while+read
do
++++((count%2B%2B))
done+<+file++++
echo+"line+count:+$count"|code-block|syntax|javascript|704973|entityMap^0|V|6|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

You can use bash. Note for very large files in terms of GB, use <code>awk/wc</code>. However it should still be manageable in performance for files with a few MB.

<pre><code>declare -i count=0
while read
do
 ((count++))
done &lt; file 
echo "line count: $count"
</code></pre>

blocks|key|705213|text|如果计算第一列中的列数就足够了，请尝试以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|705214|awk+-F'\t'+'{print+NF;+exit}'+myBigFile.tsv|offset|length|style|CODE|705215|其中\t是列分隔符。|705216|entityMap^0|0|0|17|0|2|2|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@$D|N|E|O|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|P|8|@$D|Q|E|R|F|G]]|9|@]|A|$]]|$1|J|3|-4|5|6|7|S|8|@]|9|@]|A|$]]]|K|$]]

If counting number of columns in the first is enough, try the following: 

<code>awk -F'\t' '{print NF; exit}' myBigFile.tsv</code>

where <code>\t</code> is column delimiter.

blocks|key|705500|text|awk+'BEGIN{FS=","}END{print+"COLUMN+NO:+"NF+"+ROWS+NO:+"NR}'+file|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|705501|您可以使用任何分隔符作为字段分隔符，并可以查找行数和列数|unstyled|705502|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>awk 'BEGIN{FS=","}END{print "COLUMN NO: "NF " ROWS NO: "NR}' file
</code></pre>

You can use any delimiter as field separator and can find numbers of ROWS and columns

blocks|key|921362|text|简单的行数是$(wc+-l+"$file")。使用$(wc+-lL+"$file")显示行数和最长行中的字符数。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|921363|entityMap^0|6|G|P|H|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|M|8|@]|D|@]|E|$]]]|G|$]]

Simple row count is <code>$(wc -l "$file")</code>. Use <code>$(wc -lL "$file")</code> to show both the number of lines and the number of characters in the longest line.

blocks|key|705165|text|head+-1+file.tsv+%7Chead+-1+train.tsv+%7Ctr+'\t'+'\n'+%7Cwc+-l|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|705166|取第一行，更改制表符(或者您可以使用'，‘代替'\t’作为逗号)，计算行数。|unstyled|705167|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>head -1 file.tsv |head -1 train.tsv |tr '\t' '\n' |wc -l
</code></pre>

take the first line, change tabs (or you can use ',' instead of '\t' for commas), count the number of lines.

blocks|key|921539|text|Perl解决方案：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|921540|perl+-ane+'$maxc+=+$#F+if+$#F+>+$maxc;+END{$maxc%2B%2B;+print+"max+columns:+$maxc\nrows:+$.\n"}'+file|offset|length|style|CODE|921541|如果您的输入文件以逗号分隔：|921542|perl+-F,+-ane+'$maxc+=+$#F+if+$#F+>+$maxc;+END{$maxc%2B%2B;+print+"max+columns:+$maxc\nrows:+$.\n"}'+file|921543|输出：|921544|max+columns:+5
rows:+2|code-block|syntax|javascript|921545|-a将输入行自动拆分到@F数组|921546|$#F是列数-1|921547|的-F,字段分隔符，而不是空白|921548|$.是行号(行数)|921549|entityMap^0|0|0|2P|0|0|0|2T|0|0|0|0|2|B|2|0|0|3|0|1|3|0|0|2|0^^$0|@$1|2|3|4|5|6|7|12|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|13|8|@$D|14|E|15|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|16|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|17|8|@$D|18|E|19|F|G]]|9|@]|A|$]]|$1|L|3|M|5|6|7|1A|8|@]|9|@]|A|$]]|$1|N|3|O|5|P|7|1B|8|@]|9|@]|A|$Q|R]]|$1|S|3|T|5|6|7|1C|8|@$D|1D|E|1E|F|G]|$D|1F|E|1G|F|G]]|9|@]|A|$]]|$1|U|3|V|5|6|7|1H|8|@$D|1I|E|1J|F|G]]|9|@]|A|$]]|$1|W|3|X|5|6|7|1K|8|@$D|1L|E|1M|F|G]]|9|@]|A|$]]|$1|Y|3|Z|5|6|7|1N|8|@$D|1O|E|1P|F|G]]|9|@]|A|$]]|$1|10|3|-4|5|6|7|1Q|8|@]|9|@]|A|$]]]|11|$]]

Perl solution:

<code>perl -ane '$maxc = $#F if $#F &gt; $maxc; END{$maxc++; print "max columns: $maxc\nrows: $.\n"}' file</code>

If your input file is comma-separated:

<code>perl -F, -ane '$maxc = $#F if $#F &gt; $maxc; END{$maxc++; print "max columns: $maxc\nrows: $.\n"}' file</code>

output:

<pre><code>max columns: 5
rows: 2
</code></pre>

<code>-a</code> autosplits input line to <code>@F</code> array 
<code>$#F</code> is the number of columns -1 
<code>-F,</code> field separator of , instead of whitespace 
<code>$.</code> is the line number (number of rows)

blocks|key|705255|text|在纯bash+(没有awk、perl或其他语言)中计算第一行列数的一种非常简单的方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|705256|read+-r+line+<+$input_file
ncols=`echo+$line+%7C+wc+-w`|code-block|syntax|javascript|705257|如果您的数据格式化得当，这将起作用。|705258|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

A very simple way to count the columns of the first line in pure bash (no awk, perl, or other languages):

<pre><code>read -r line &lt; $input_file
ncols=`echo $line | wc -w`
</code></pre>

This will work if your data are formatted appropriately.

blocks|key|921721|text|下面的代码将完成这项工作，并允许您指定字段分隔符。这对于包含超过20k行的文件特别有用。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|921722|awk+'BEGIN+{+
++FS="%7C";+
++min=10000;+
}
{+
++if(+NF+>+max+)+max+=+NF;+
++if(+NF+<+min+)+min+=+NF;
}+
END+{+
++print+"Max="+max;+
++print+"Min="+min;+
}+'+myPipeDelimitedFile.dat|code-block|syntax|javascript|921723|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Following code will do the job and will allow you to specify field delimiter. This is especially useful for files containing more than 20k lines. 

<pre><code>awk 'BEGIN { 
 FS="|"; 
 min=10000; 
}
{ 
 if( NF &gt; max ) max = NF; 
 if( NF &lt; min ) min = NF;
} 
END { 
 print "Max=" max; 
 print "Min=" min; 
} ' myPipeDelimitedFile.dat
</code></pre>

Say I have a large file with many rows and many columns. I'd like to find out how many rows and columns I have using bash.

How do I count the number of rows and columns in a file using bash?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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假设我有一个多行多列的大文件。我想知道我使用bash有多少行和多少列。

问如何使用bash计算文件中的行数和列数？
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